[英]In Python 3, how can I run two functions at the same time?
我有 2 個功能:一個讀取文本文件,另一個在按下某個鍵時更改該文本文件。 我需要我的代碼每隔幾秒打印一次文本文件,同時監視按鍵以更改文件。 這可能嗎?我該怎么做?
我試過這個,但它不起作用。
def read_file():
color = open("color.txt", "r")
current_color = color.read()
color.close()
if current_color == "green":
print("GREEN")
elif current_color == "blue":
print("BLUE")
time.sleep(5)
def listen_change():
if keyboard.is_pressed('g'):
f = open("color.txt", "w")
f.write("green")
f.close()
elif keyboard.is_pressed('b'):
f = open("color.txt", "w")
f.write("blue")
f.close()
編輯:這是我嘗試多線程的方式
from threading import Thread
if __name__ == '__main__':
Thread(target=read_file()).start()
Thread(target=listen_change()).start()
我有兩個功能:一個讀取文本文件,另一個在按下鍵時更改該文本文件。 我需要我的代碼每隔幾秒鍾打印一次文本文件,同時監視按鍵以更改文件。 這可能嗎?我該怎么做?
我試過這個,但它不起作用。
def read_file():
color = open("color.txt", "r")
current_color = color.read()
color.close()
if current_color == "green":
print("GREEN")
elif current_color == "blue":
print("BLUE")
time.sleep(5)
def listen_change():
if keyboard.is_pressed('g'):
f = open("color.txt", "w")
f.write("green")
f.close()
elif keyboard.is_pressed('b'):
f = open("color.txt", "w")
f.write("blue")
f.close()
編輯:這是我嘗試多線程的方式
from threading import Thread
if __name__ == '__main__':
Thread(target=read_file()).start()
Thread(target=listen_change()).start()
target
參數必須是 function。您正在立即調用函數,而不是傳遞對 function 的引用。
函數需要循環。
使用join()
等待線程退出。
使用鎖來防止同時讀取和寫入文件,這可能會在部分 state 中讀取文件。
import keyboard
from threading import Thread, Lock
mutex = Lock()
def read_file():
while True:
with mutex:
with open("color.txt", "r") as color:
current_color = color.read()
if current_color == "green":
print("GREEN")
elif current_color == "blue":
print("BLUE")
time.sleep(5)
def listen_change():
while True:
if keyboard.is_pressed('g'):
with mutex:
with open("color.txt", "w"):
f.write("green")
elif keyboard.is_pressed('b'):
with mutex:
with open("color.txt", "w"):
f.write("blue")
if __name__ == '__main__':
t1 = Thread(target = read_file)
t2 = Thread(target = listen_change)
t1.start()
t2.start()
t1.join() # Don't exit while threads are running
t2.join()
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