在 python 中使用正則表達式在字符串列表中查找匹配關鍵字后的下一個單詞

Question

我有一個字符串列表，我想在每個字符串中的特定關鍵字之后提取下一個單詞。

當我使用 lambda function 遍歷列表時，我得到的是整個字符串，而不僅僅是關鍵字后的下一個詞：

import re
s = ["The job ABS is scheduled by Bob.", "The job BFG is scheduled by Alice."]
user = filter(lambda i:re.search('(?<=The job )(\w+)',i),s)
print(*user)

output: The job ABS is scheduled by Bob. The job BFG is scheduled by Alice.

但是，當我為單個字符串嘗試相同的代碼時，它給出了正確的 output：

import re
s = "The job ABS is scheduled by Bob."
user = re.search('(?<=The job )(\w+)',s)
print(user.group())

output: ABS

我怎樣才能從第一個代碼片段中得到 output like (ABS, BFG) ？

Answer 1

您可以使用

import re
s = ["The job ABS is scheduled by Bob.", "The job BFG is scheduled by Alice."]
rx = re.compile(r'(?<=The job )\w+')
user = tuple(map(lambda x: x.group() or "", map(rx.search, s)))
print(user)

請參閱Python 演示。

或者，如果可以有任意數量的空格，請使用

rx = re.compile(r'The\s+job\s+(\w+)')
user = tuple(map(lambda x: x.group(1) or "", map(rx.search, s)))

Output：

('ABS', 'BFG')

這里， map(rx.search, s)返回一個迭代器到匹配數據對象或None s，外層map(lambda x: x.group(...) or "", ...)獲取值組的匹配項（與.group()的整個匹配項或與.group(1)的第 1 組值），如果沒有匹配項，則返回空字符串。

Answer 2

你可以簡化這個：

import re

arr = ["The job ABS is scheduled by Bob.", "The job BFG is scheduled by Alice."]
user = [re.findall('(?<=The job )\w+', s) for s in arr]
print (user)
print (tuple(user))

Output：

[['ABS'], ['BFG']]
(['ABS'], ['BFG'])