[英]How Get Data from this Json in Flutter?
{ "features": [ { "Data": { "First Name": "AA1", "Last Name": "AA2", "Address": "AA3", "Company": "AA4", } }, "Data": { "First Name": "BB1", "Last Name": "BB2", "Address": "BB3", "Company": "BB4", } }, { "Data": { "First Name": "CC1", "Last Name": "CC2", "Address": "CC3", "Company": "CC4", } }, ...... ] }
我不知道這樣做的正確方法應該是什么
如何從具有相同名稱“數據”的 object 的 object 數組中獲取數據
從 JSON 獲取數據時,您應該創建一個 Model 來描述您要解析的 object(在本例中為Data
對象)。 然后,您可以創建一個方法來解析 JSON 字符串中的 object(或對象列表):
object 將如下所示:
class Data {
Data({
this.firstName,
this.lastName,
this.address,
this.company,
});
String firstName;
String lastName;
String address;
String company;
factory Data.fromJson(Map<String, dynamic> json) => Data(
firstName: json["First Name"],
lastName: json["Last Name"],
address: json["Address"],
company: json["Company"],
);
Map<String, dynamic> toJson() => {
"First Name": firstName,
"Last Name": lastName,
"Address": address,
"Company": company,
};
}
然后,您可以像這樣解析 object:
// features will be the list of your JSON objects
var features = jsonData["features"];
// Here you parse it to the list of Data object
var datas = List<Data>.from(features.map((item) => Data.fromJson(item["Data"])));
對於 Model 創建,為了節省時間您也可以查看此工具。 它支持從您的 JSON 字符串創建 Model。
您必須像這樣聲明 model :
class Feature {
Feature(DataModel dataModel);
}
class DataModel {
DataModel(
{firstName: firstName, lastName: lastName, address: address, company: company});
factory DataModel.fromJson(Map<String, dynamic> json) {
return DataModel(
firstName: json['firstName'],
lastName: json['lastName'],
address: json['address'],
company: json['company'],
);
}
}
之后,您必須使用如下代碼對其進行反序列化:
var results = jsonDecode(yourJsonString)["features"];
return (results as List)
.map((e) => DataModel(e))
.toList();
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