[英]Group by latest value sql
Forecast date date Value Object Demand or supply
01-01-2016 00:30 12-10-2019 00:00 85 Ice-cream Demand
04-07-2018 02:59 26-12-2019 00:00 83 Crisps Supply
07-08-2018 03:25 29-02-2020 00:00 50 Juice Demand
29-10-2018 03:25 09-05-2020 00:00 76 Juice Supply
25-02-2019 03:25 07-08-2020 00:00 74 Juice Demand
01-07-2019 03:25 11-10-2020 00:00 69 Crisps Demand
17-10-2019 03:25 17-12-2020 00:00 77 Meal Supply
06-01-2020 03:25 29-03-2021 00:00 87 Eggs Demand
我有一個 dataframe 像上面一樣,隨着更多數據可用,預測會在特定日期不斷出現
我想獲得每個 object 和單獨分組需求和供應的特定日期的最新預測值。
Logic-
-Latest forecast date for each date value and object
- Group demand/supply and object with Date desc
所需 output
Forecast Date Date Demand or supply Object Value
01-01-2020 01-11-2021 Demand Ice-Cream 60
01-01-2020 01-10-2021 Demand Ice-Cream 80
01-01-2020 01-09-2021 Demand Crisps 70
01-01-2020 01-08-2020 Supply Crisps 70
01-11-2019 01-07-2020 Supply Crisps 85
01-11-2019 01-06-2020 Supply Crisps 80
因此,為了清楚地說明日期列中的條目 - 我希望該值是最新預測日期中的值。 - 然后按需求/供應對表格進行分組,然后按 object 分組,最后按日期分組,因此在需求/供應側為每個 object 獲得相應的時間序列值
如果我理解正確,您可以使用row_number()
:
select t.*
from (select t.*,
row_number() over (partition by object, demand_group, date order by forecast_date desc) as seqnum
from t
) t
where seqnum = 1;
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