在逗號分隔的字符串中如何過濾數組 object 的唯一值

Question

我有這個數組，其中 'data_type' 以逗號分隔的字符串保存值：

原始數組：

var getGroups = [
{ id: 52, data_type: "Prices & Volumes,Holdings,Reference Data" },
{ id: 51, data_type: "Prices & Volumes,Holdings,Reference Data" },
{ id: 49, data_type: "Fundamentals,Holdings,Corporate Actions,Reference Data" },
{ id: 25, data_type: "Holdings,Corporate Actions,Reference Data" }
]

如何捕獲、過濾和構建具有所有唯一值的新數組？

目標數組：

var targetArray = [
"Prices & Volumes",
"Holdings",
"Reference Data",
"Fundamentals",
"Corporate Actions"
]

console.log('targetArray:');
console.log(targetArray);

["Prices & Volumes", "Holdings", "Reference Data", "Fundamentals", "Corporate Actions"]

這是一個小提琴： https://jsfiddle.net/grnewkzs/1/

Answer 1

const getGroups = [
  { id: 52, data_type: "Prices & Volumes,Holdings,Reference Data" },
  { id: 51, data_type: "Prices & Volumes,Holdings,Reference Data" },
  { id: 49, data_type: "Fundamentals,Holdings,Corporate Actions,Reference Data" },
  { id: 25, data_type: "Holdings,Corporate Actions,Reference Data" }
];

const values = getGroups.map(item => item.data_type.split(','))
const sets = new Set([].concat(...values))
const array = Array.from(sets)

你需要知道為什么以及如何，或者你什么都沒有……那很糟糕。

Answer 2

 var getGroups = [ { id: 52, data_type: "Prices & Volumes,Holdings,Reference Data" }, { id: 51, data_type: "Prices & Volumes,Holdings,Reference Data" }, { id: 49, data_type: "Fundamentals,Holdings,Corporate Actions,Reference Data" }, { id: 25, data_type: "Holdings,Corporate Actions,Reference Data" } ] var targetArray = []; for (i=0;i<getGroups.length;i++){ items = getGroups[i]["data_type"].split(","); for (j=0;j<items.length;j++){ if (targetArray.indexOf(items[j]) === -1){targetArray.push(items[j]);} } } console.log('targetArray:'); console.log(targetArray);