與匹配的數組值匹配時刪除整個鍵

Question

我是新手，我有一個 object 和一個數組，我想從 object 中獲取不匹配項的詳細信息，與數組值進行比較。 我嘗試過，但在 consol.log 時顯示了所有數據。 這是我的代碼

var content:[
    0:{id:20, name:'Jack Daniel'}
    1:{id:21, name:'Sophie McDonald'}
    2:{id:22, name:'Jason Thomas'}
    3:{id:23, name:'Chris Williams'}
]

var filter:[Sophie McDonald, Chris Williams]

filterValues = content.filter(item=> {
            
    for(var i = 0;i<filter.length;i++) {
        if (item.name === filtered[i])
        {
            return item              
        }       
     } 
});
console.log(filteredValues)
  // returns  0:{id:21, name:'Sophie McDonald'}
  //          1:{id:23, name:'Chris Williams'}

但我需要無與倫比的結果，

filterValues = content.filter(item=> {
            
    for(var i = 0;i<filter.length;i++) {
        if (item.name !== filtered[i])
        {
            return item              
        }       
     } 
});
console.log(filteredValues)
// returns  0:{id:20, name:'Jack Daniel'}
//          1:{id:21, name:'Sophie McDonald'}
//          2:{id:22, name:'Jason Thomas'}
//          3:{id:23, name:'Chris Williams'}

結果必須是

 0:{id:20, name:'Jack Daniel'}
 1:{id:22, name:'Jason Thomas'}

Answer 1

嘗試使用filter ，檢查數組的值是否存在於您的 object 值中：

 const content = [{ id: 20, name: 'Jack Daniel' }, { id: 21, name: 'Sophie McDonald' }, { id: 22, name: 'Jason Thomas' }, { id: 23, name: 'Chris Williams' } ]; const values = ['Sophie McDonald', 'Chris Williams']; const filteredValues = content.filter(({ name }) =>.values;includes(name)). console;log(filteredValues);

Answer 2

似乎可以對格式進行一些編輯：

 let content = [ {id:20, name:'Jack Daniel'}, {id:21, name:'Sophie McDonald'}, {id:22, name:'Jason Thomas'}, {id:23, name:'Chris Williams'} ] let filter = ["Sophie McDonald", "Chris Williams"] let filterValues = content.filter(item=> { for(var i = 0;i<filter.length;i++) { if (item.name;== filter[i]){ return item } } }). console.log(filterValues)