禁用 sys.stdout, err, .. 在終端打印？

Question

我有一個 pyqt5 GUI，我從它開始。/mygui.py。 在 myguy.py 中，我添加了一個 class 以通過彈出窗口 window 處理異常（從http://timlehr.com/python-exception-boxt/hooks-with-message復制）。 然而，雖然異常現在出現在彈出窗口 window 中，但它們仍然被寫入終端。 我怎樣才能刪除這個？ 這是上面鏈接中的 class，可能需要更改/添加：

import sys
import traceback
import logging
# basic logger functionality
log = logging.getLogger(__name__)
handler = logging.StreamHandler(stream=sys.stdout)
log.addHandler(handler)

def show_exception_box(log_msg):
    """Checks if a QApplication instance is available and shows a messagebox with the exception message. 
    If unavailable (non-console application), log an additional notice.
    """
    if QtWidgets.QApplication.instance() is not None:
            errorbox = QtWidgets.QMessageBox()
            errorbox.setText("Oops. An unexpected error occured:\n{0}".format(log_msg))
            errorbox.exec_()
    else:
        log.debug("No QApplication instance available.")
 
class UncaughtHook(QtCore.QObject):
    _exception_caught = QtCore.Signal(object)
 
    def __init__(self, *args, **kwargs):
        super(UncaughtHook, self).__init__(*args, **kwargs)

        # this registers the exception_hook() function as hook with the Python interpreter
        sys.excepthook = self.exception_hook

        # connect signal to execute the message box function always on main thread
        self._exception_caught.connect(show_exception_box)
 
    def exception_hook(self, exc_type, exc_value, exc_traceback):
        """Function handling uncaught exceptions.
        It is triggered each time an uncaught exception occurs. 
        """
        if issubclass(exc_type, KeyboardInterrupt):
            # ignore keyboard interrupt to support console applications
            sys.__excepthook__(exc_type, exc_value, exc_traceback)
        else:
            exc_info = (exc_type, exc_value, exc_traceback)
            log_msg = '\n'.join([''.join(traceback.format_tb(exc_traceback)),
                                 '{0}: {1}'.format(exc_type.__name__, exc_value)])
            log.critical("Uncaught exception:\n {0}".format(log_msg), exc_info=exc_info)

            # trigger message box show
            self._exception_caught.emit(log_msg)

Answer 1

根據您的邏輯，您將 StreamHandler 用作將日志發送到 sys.stdout（在本例中為終端）的處理程序，如果您不希望發送它，請使用 NullHandler：

log = logging.getLogger(__name__)
handler = logging.NullHandler() # StreamHandler(stream=sys.stdout)
log.addHandler(handler)