[英]Oracle XMLTYPE extract root prolog value
SELECT * FROM v$version;
*Oracle Database 12c Enterprise Edition Release 12.1.0.2.0 - 64bit Production
PL/SQL Release 12.1.0.2.0 - Production
"CORE 12.1.0.2.0 Production"
TNS for Linux: Version 12.1.0.2.0 - Production
NLSRTL Version 12.1.0.2.0 - Production*
我有 XML 的示例查詢,如下所示:
with t(xml) as
(
select xmltype(
'<SSO_XML
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
TimeStamp="2020-08-05T21:57:23Z"
Target="Production"
Version="1.0"
TransactionIdentifier="PLAN_A"
SequenceNmbr="123456"
xmlns="http://www.w3.org/2001/XMLSchema">
<PlanCode PlanCodeCode="CHOICE">
<S_DAYS FARE="10" Start="2020-08-07" End="2020-10-30" Mon="true" Tue="true" Weds="true" Thur="true" Fri="true" Sat="true" Sun="true">
<STUDENT>
<DIVISION ORIGINAL="150.05" Code="Flat" S_CODE="1" />
<DIVISION ORIGINAL="150.05" Code="Flat" S_CODE="2" />
</STUDENT>
</S_DAYS>
</PlanCode>
</SSO_XML>')
from dual
)
select h.PlanCodeCode
,b.Original
,b.code
,b.s_code
from t
cross join
xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'/SSO_XML'
passing t.xml
columns PlanCodeCode varchar2(100) path './PlanCode/@PlanCodeCode',
attributes xmltype path './PlanCode'
) h
cross join xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'PlanCode/S_DAYS/STUDENT/DIVISION'
passing h.attributes
columns
ORIGINAL number path '@ORIGINAL',
Code varchar2(100) path '@Code',
S_CODE number path '@S_CODE'
) b;
Output:
我正在嘗試在查詢或新查詢中獲取以下值:有什么辦法嗎? 任何幫助/方向表示贊賞。
您只需以這種方式完成您的第一個 XMLTABLE 查詢 (h):
target varchar2(100) path '/SSO_XML/@Target',
transactionId varchar2(100) path '/SSO_XML/@TransactionIdentifier'
您正在嘗試包含兩個屬性,它們使用@
前綴訪問; 因此您的查詢可以修改為:
select h.PlanCodeCode
,h.target
,h.transactionIdentifier
,b.Original
,b.code
,b.s_code
from t
cross join
xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'/SSO_XML'
passing t.xml
columns PlanCodeCode varchar2(100) path './PlanCode/@PlanCodeCode',
target varchar2(100) path '@Target',
transactionIdentifier varchar2(100) path '@TransactionIdentifier',
attributes xmltype path './PlanCode'
) h
...
在這種情況下,您也可以在單個 XMLTable 調用中執行此操作,該調用更短,但可能更難閱讀和維護:
select b.PlanCodeCode
,b.target
,b.transactionIdentifier
,b.Original
,b.code
,b.s_code
from t
cross join
xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'/SSO_XML/PlanCode/S_DAYS/STUDENT/DIVISION'
passing t.xml
columns PlanCodeCode varchar2(100) path './../../../@PlanCodeCode',
target varchar2(100) path './../../../../@Target',
transactionIdentifier varchar2(100) path './../../../../@TransactionIdentifier',
ORIGINAL number path '@ORIGINAL',
Code varchar2(100) path '@Code',
S_CODE number path '@S_CODE'
) b;
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