錯誤：C6386：寫入“newArr”時緩沖區溢出：可寫大小為“int current_size*1”字節，但可能寫入“2”字節

Question

代碼會打印出來。 但它給出了那個錯誤。 目標是將其作為示例打印出來： 4 as：aaaa 8 as：aaaaaaaaa 12 as：aaaaaaaaaaaa 16 as：aaaaaaaaaaaaaaaa

#include<iostream>
using namespace std;
int current_size = 4;
int resize_step = 4;

void add_number(char* &arr, int count, char x){
   if(count == current_size){
       current_size += resize_step;
       char* newArr = new char[current_size];
       
       for(int i=0;i<count;i++) newArr[i] = arr[i];
       delete arr;
       arr = newArr;
   }
   arr[count-1] = x;
}


//After
int main(){
   char* arr = new char[current_size];
   for(int count=0;count<4;count++){
       add_number(arr, count+1, '1' + count);
   }
   for(int i=0;i<4;i++) cout<<arr[i]<<" ";
   return 0;
}

Answer 1

所以我重寫了代碼。 但預期的 output 是：預期答案：4 as：aaaa 8 as：aaaaaaaa 12 as：aaaaaaaaaaaa 16 as：aaaaaaaaaaaaaaaa

我只得到第一行4 作為 aaaa

#include <iostream>
using namespace std;

int current_size = 4;
int resize_step = 4;

//This functions add the value x at the last position in the array
//The count of elements is indicated by the variable count
//If the array is already at maximum it resizes
//The array starts at current_size size and resizes in resize_step intervals
void add_number(char*& arr, int count, char x)
{
    //Your code starts here
    arr = new char[current_size];
    for (int i = 0; i < current_size; i++)
    {
        //arr[i] = x;
        if (count >= current_size)
        {
            current_size += resize_step;
            char* array2 = new char[current_size - resize_step];
            for (int j = 0; j < sizeof(array2); j++)
            {
               array2[j] = arr[j];
            }
            delete[](arr);
            arr = array2;
        }
        arr[i] = x;
    }
}
int main() {
    char* arr = new char[current_size];
    char x = 'a';
    int element = 8;
    add_number(arr, element, x);
    for (int i = 0; i < current_size; i++)
    {
        cout << arr[i];
    }
    return 0;
}