如何根據另一個數組過濾來自一個數組的數據

Question

假設我有 2 個數組arr1=["a","b","c","d","e"]基於arr2 = [1,3]所需 output 是arr1 = ["b","d"]

Answer 1

valueArray = ["a","b","c","d","e"]; // arr1
indexArray = [1,3]; // arr2

valueArray = indexArray.map(index => valueArray[index]);

console.log(valueArray);

Answer 2

只需執行以下命令：

 const arr1=["a","b","c","d","e"]; const arr2 = [1,3]; const filteredArray = arr1.filter((_,index)=>{ return arr2.includes(index) }); console.log(filteredArray)

Answer 3

我假設您想要第一個數組的值以及第二個數組中提供的索引。 您可以通過以下方法實現這一點

arr2.forEach(value => d.push(arr1[value]))

Answer 4

您可以使用 map：

const arr3 = arr2.map(i => aar1[i])