[英]Convert tuple into dict and choose dict key names
我有以下元組: (1234234, 23, 0)
我想把它變成以下形式的字典:
{
app: 1234234,
sdk: 23,
done: 0,
}
怎樣才能做到這一點?
更新:這個問題與這個問題不同,因為它並不意味着它只能通過使用兩個元組來解決。
類似下面的東西
values = (1234234, 23, 0)
keys = ['app', 'sdk', 'done']
d = {k: values[idx] for idx, k in enumerate(keys)}
print(d)
output
{'app': 1234234, 'sdk': 23, 'done': 0}
@balderman 的另一種方法:
values = (1234234, 23, 0)
keys = ['app', 'sdk', 'done']
d = dict(zip(keys, values))
t = (1234234, 23, 0)
keys = ["app", "sdk", "done"]
d = {}
for num in t:
key = keys[t.index(num)]
d[key] = num
此代碼將遍歷元組中的數字並將鍵分配給字典中的數字。
a)如果您想手動選擇鍵(用戶通過 shell 輸入),您可以執行以下操作:
values = (1234234, 23, 0)
yourdict = {input(f"insert key fot value {value}: "): value for value in values}
output:
>>> insert a key for value 1234234: value1
>>> insert a key for value 23: value2
>>> insert a key for value 0: value3
{"value1": 1234234, "value2": 23, "value3": 0}
b)如果您想從鍵列表中自動執行此操作:
values = (1234234, 23, 0)
keys = ["key1", "key2", "key3"]
yourdict = {keys[count]: value for count, value in enumerate(values)}
output:
{"key1": 1234234, "key2": 23, "key3": 0}
c)如果您想以數字方式分配它們:
values = (1234234, 23, 0)
yourdict = {count: value for count, value in enumerate(values)}
output:
{0: 1234234, 1: 23, 2: 0}
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