[英]WildFly Could not find resource for full path (no XML, using commandline deployment)
[英]Could not find path for REST resource (Wildfly 22.0.0 deployment)
當我將 Web 應用程序部署到 Wildfly 22.0.0 時,我似乎找不到 Rest 資源的路徑:
Could not find resource for full path: http://127.0.0.1:8080/CourseManagementApplication/rest/api/assignments/list
我不確定我做錯了什么。
web.xml
<servlet>
<servlet-name>RestApplication</servlet-name>
<servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
<init-param>
<param-name>javax.ws.rs.Application</param-name>
<param-value>impl.rest.application.RestApplication</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>RestApplication</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
RestApplication.java
@ApplicationPath("/api")
public class RestApplication extends Application {
@Override
public Set<Class<?>> getClasses() {
final Set<Class<?>> classes = new HashSet<>();
classes.add(AssignmentResource.class);
return classes;
}
}
分配資源.java
@Path("/assignments")
public class AssignmentResource {
@GET
@Path("/list")
@Produces({MediaType.APPLICATION_JSON, MediaType.APPLICATION_XML})
public Response getAssignments() {
return ........
}
}
我認為可以通過 URI [Root]/rest/api/assignments/list 訪問該資源。 我不明白為什么這條路行不通。
這段代碼有兩個問題:
1- 正如上面評論中提到的,我不應該同時使用 servlet-mapping 和 @ApplicationPath。 所以我刪除了RestApplication.java中的@ApplicationPath注釋。
2-我不知道,要使用url模式與/*
不同,您不僅應該在server-mapping
中定義它,而且還必須將context-param
添加到Z2567A5EC97AC9705EB7AC2C9884013E840F.98840FER tister -Param中
<context-param>
<param-name>resteasy.servlet.mapping.prefix</param-name>
<param-value>/rest</param-value>
</context-param>
因此端點在http://127.0.0.1:8080/CourseManagementApplication/rest/assignments/list中正確可用
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