Oracle 按客戶和日期分組

Question

我有一個有效的休閑查詢：

SELECT count(cand_id) as candidates, SB.client_id as client
            FROM REPLIES r
            JOIN clients sb on sb.main_acc_id = r.acc_id
            where reply_dt >= TO_DATE('2021-02-08 00:00:00', 'YYYY-MM-DD HH24:MI:SS')
            AND reply_dt <= TO_DATE('2021-02-15 23:59:59', 'YYYY-MM-DD HH24:MI:SS')
            AND sb.status = 'A'
            GROUP BY client_id

它產生如下結果：

 Candidates| Clients
     2     |  client 1
     4     |  cleint 2
    56     |  client whatever..  

我將如何 go 關於在給定日期范圍內按天和客戶細分候選人數量？ 所以它會顯示當天，沒有候選人，客戶

Answer 1

這是做你想做的嗎？

SELECT TRUNC(r.reply_dt), sb.client_id, COUNT(cand_id) as candidates
FROM REPLIES r JOIN
     clients sb 
     ON sb.main_acc_id = r.acc_id
WHERE sb.status = 'A'
GROUP BY TRUNC(r.reply_dt), client_id