[英]How to make a destructuring of this array of objects
我正在嘗試對我的subItems
數組的元素使用解構來獲取直接引用links
和open
屬性的變量。
具體來說,我正在嘗試使用以下代碼,如注釋中指定的那樣失敗。
const [{links, open}] = subItems.map(({ items }) => {
document.getElementById(items);
}); // Fails: returns nothing
const {links, open} = subItems((items ) => {
return items;
}); // Fails: returns only the first `link` and `open`
// This is what the `subItems` array looks like:
export const subItems = [
{
links: [
{ title: 'ret', to: '#' },
{ title: 'def', to: '#' },
{ title: 'rev', to: '#' },
{ title: 'red', to: '#' },
{ title: 'im', to: '#' },
{ title: 'glossar', to: '#' }
],
open: true
},
{
links: [
{ title: 'recloud', to: '#' },
{ title: 'broker', to: '#' },
{ title: 'mercury', to: '#' },
{ title: 'investor', to: '#' }
],
open: false
}
];
PS我是JS的新手,如果我誤解了一些瑣碎的事情,對不起。
這是否完成了您想要做的事情?:
// Gets array (but you can get it any way you want, maybe by `import`) const subItems = getSubItems(); // Loops through array (using `subItem` as the name for each array element) for(subItem of subItems){ // Destructures the current element in array (using `{...}` for objects) const {links, open} = subItem; // Collects links info (This is not needed -- just makes nicer printing) const linkString = links.reduce( (linkStr, link) => linkStr + `title:${link.title}, to:${link.to}; `, "" ); // Does something with links and open (We could print `links` instead of linkString) console.log("links: ", linkString, "\nopen: ", open, "\n\n"); } function getSubItems(){ return [ { links: [ { title: 'ret', to: '#' }, { title: 'def', to: '#' }, { title: 'rev', to: '#' }, { title: 'red', to: '#' }, { title: 'im', to: '#' }, { title: 'glossar', to: '#' } ], open: true }, { links: [ { title: 'recloud', to: '#' }, { title: 'broker', to: '#' }, { title: 'mercury', to: '#' }, { title: 'investor', to: '#' } ], open: false } ]; }
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