正則表達式從字符串中提取特定值

Question

在這個控制台中，我有要從這個字符串中提取的數據

在 Rails 控制台中獲取的字符串

  Ace Janitorial Service. Inc.                                                                  Invoice
4901 MORENA BLVD. STE 907

SAN DIEGO, CA 92117 US
(858) 270-7004
rbeckerley@acejanitorialsd.com

www.acejanitorialsd.com



            BILL TO

            Lab Fellows, Inc.
            11011 N Torrey Pines Rd,
            La Jolla, Ca 92037




INVOICE #            DATE              TOTAL DUE            DUE DATE           TERMS             ENCLOSED
31104                02/15/2021        $1,251.92            03/17/2021         Net 30





DATE                  DESCRIPTION                                         QTY                RATE           AMOUNT

01/19/2021            Refrigerator Cleaning                                  2               20.00            40.00
                      Clean interior of Refrigerators

02/01/2021            Janitorial Services                                5,564                0.10           556.40
                      2x's a week Labs

02/01/2021            Janitorial Services                                8,194                0.08           655.52
                      2x's a week office space
Thank you for your continued business!!
                                                             BALANCE DUE                             $1,251.92

我試過下面的代碼

def extract_invoice_no(msgBody)
      pattern = [ "invoice_number", "invoice number", "invoicenumber", "InvoiceNumber", "Invoice number", "Invoice Number", "Invoice_Number", "invoice #", "invoice#", "Invoice #", "Invoice#", "InvoiceNo", "Invoice No", "Invoice no","Invoice_No", "invoice no", "invoice_no", "invoiceno"]
      invoiceNo = '';
      pattern.each do |each|
        if (msgBody.include? each)
          invoiceNo = msgBody.split(each)[1].gsub(':','').strip.split(" ")[0]
          puts 'invoice no ', invoiceNo
          break
        end
      end
      return invoiceNo
    end

要求：我需要使用 ruby 代碼從下面的 output 中提取 INVOICE #（Invoice Number）。

Output 獲得日期：日期

Output 需要： 31104

任何幫助都可能對我繼續前進非常有用。

Answer 1

每個模式都以invoice或Invoice開頭。

因此，您可以將文本小寫，圍繞/^invoice/拆分，獲取第二個元素。 然后，您得到第二行，再次拆分，並得到invoice的第一個“單詞”：

msgBody.downcase.split(/^invoice/)[1].lines[1].split[0]
#=> 31104