在 java 上遞減一定量

Question

我正在嘗試創建一個程序，其中用戶輸入的數字會減少一定數量。 像這樣的東西：

Update by (Increment/Decrement):decrement
Enter starting number:15
Enter update number:3
Enter end number:3
loop#1  value=15
loop#2  value=12

結束編號是循環停止的位置，更新編號是起始編號應該減少多少。 到目前為止，這是我擁有的代碼，我被困在如何保持循環直到結束數字。

package jaba;
import java.util.Scanner;


public class loop {

public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    Scanner input = new Scanner(System.in);

    System.out.print("Update by (Increment/Decrement):");
    String Decrement = scan.nextLine();
    
    System.out.print("Enter starting number:");
    String number = scan.nextLine();
    
    System.out.print("Enter update number:");
    String upnumber = scan.nextLine();
    
    System.out.print("Enter end number:");
    String endnumber = scan.nextLine();
    
    
    
    int i,j;
    
    i = 15;
    j = 1;
    
    do {
        
        System.out.println("loop#" +j+ "\tvalue="+i);
        j++;
        
        
        
        }while(i<15);
            
        i = i-3;
        
        System.out.println("loop#" +j+ "\tvalue="+i);
        };
        
        
}

Answer 1

像這樣的東西怎么樣：

public class loop {

    public enum Operation {INCREMENT, DECREMENT, INVALID}

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);

        System.out.print("Update by (Increment/Decrement):");
        String operationString = scan.nextLine();

        System.out.print("Enter starting number:");
        String numberString = scan.nextLine();

        System.out.print("Enter update number:");
        String upnumberString = scan.nextLine();

        System.out.print("Enter end number:");
        String endnumberString = scan.nextLine();

        // Determine and parse stuff
        int startNumber = Integer.parseInt(numberString);
        int updateNumber = Integer.parseInt(upnumberString);
        int endNumber = Integer.parseInt(endnumberString);
        // Parse operation, but assume invalid operation
        Operation operation = Operation.INVALID;
        if (operationString.equalsIgnoreCase("increment")) {
            operation = Operation.INCREMENT;
        } else if (operationString.equalsIgnoreCase("decrement")) {
            operation = Operation.DECREMENT;
        }

        // now do the "meat" of the assignment
        int loopNumber = 0; // we'll keep the loop number as a separate counter
        switch (operation) {
            case INCREMENT:
                for (int i = startNumber; i < endNumber; i = i + updateNumber) {
                    loopNumber++;
                    performAssignmentPrinting(loopNumber, i);
                }
                break;

            case DECREMENT:
                for (int i = startNumber; i > endNumber; i = i - updateNumber) {
                    loopNumber++;
                    performAssignmentPrinting(loopNumber, i)
                }
                break;

            case INVALID:
            default:
                throw new IllegalStateException("Please enter supported operation! (increment/decrement)");
        }
    }

    private static void performAssignmentPrinting(int loopNumber, int value) {
        System.out.println("loop#" + loopNumber + "\tvalue=" + value);
    }
}

或 do/while 版本：

        // now do the "meat" of the assignment
        int currentNumber = startNumber;
        int loopNumber = 0; // we'll keep the loop number as a separate counter

        do {
            loopNumber++;
            switch (operation) {
                case INCREMENT:
                    currentNumber += updateNumber;
                    performAssignmentPrinting(loopNumber, currentNumber);
                    break;

                case DECREMENT:
                    currentNumber -= updateNumber;
                    performAssignmentPrinting(loopNumber, currentNumber);
                    break;

                case INVALID:
                default:
                    throw new IllegalStateException("Please enter supported operation! (increment/decrement)");
            }

        } while (currentNumber != endNumber);

Answer 2

你有i = i-3; 出循環。 將 i 的遞減移動到循環中：

    do {
        System.out.println("loop#" + j + "\tvalue=" + i);
        j++;
        i = i - 3;
    } while (i > endnumber);

Answer 3

For 循環是您程序的解決方案。 for(a; b; c) {...}
谷歌 for 循環是如何工作的。 並嘗試了解 a、b、c 三個部分的工作原理。

偽：

// if decrease mode
    // for (i = upperbound ; i >= lowerbound ; i-= decrement)
        // print i

// if increase mode
    // for (i = lowerbound ; i <= upperbound ; i+= increment)
        // print i

更新：這足以讓您開始並在您的旅程中添加更多驗證。