如何進行循環以從列表中獲取特定項目？ - python

Question

關於程序：

在這個程序中，我需要獲得用戶的輸入以進行“測驗”，首先要求否。 問題，然后詢問問題文本和 4 個“答案”，並從這 4 個答案中要求正確答案。 重復沒有。 的問題。

像一個“測驗制作者”

list_of_questions 存儲問題的文本

list_of_keys 存儲所有問題的輸入“答案”（按順序）示例：

list_of_keys = [Q1_Answer1, Q1_Answer2, Q1_Answer3, Q1_Answer4, Q2_Answer1, Q2_Answer2, Q2_Answer3, Q2_Answer4, Q3_Answer1 etc...]

在 start_quiz() 我需要先打印第一個問題文本和 4 個答案，然后打印第二個問題文本和 4 個答案等...

使用循環從列表中獲取特定項目

但是我在下面制作的循環：只需再次打印相同的前 4 個答案。

我找不到從列表中正確獲取項目的解決方案。

我試過了，但沒有用：（超出范圍錯誤）

var1 = 0
for I in main_list:
    answer_amount = 4
    if answer_amount > 0:
        var1 += 1
        print(list_of_keys[var1])

整個代碼：

from questionclass import Question_template

main_list = []

list_of_questions = []
list_of_answers = []
list_of_keys = []


print("\n Quiz maker \n")


def make_quiz():
    X = 0
    Z = 0
    Y = 0
    amount_of_answers = 4
    question_amount = int(input(" Enter number of questions for     your quiz: "))
    while question_amount > 0:
        question_amount -= 1
        X += 1
        list_of_questions.append(str(input(" Text for question no." + str(X) + ": ")))
        while amount_of_answers > 0:
            amount_of_answers -= 1
            Y += 1
            list_of_keys.append((str(Y) + ".") + str(input("  Answer no." + str(Y) + ": ")))
        amount_of_answers = 4
        list_of_answers.append(int(input("\nwhich answer is the correct answer?\n")))
        Y = 0
    for question in list_of_questions:
        main_list.append(Question_template(question, list_of_keys[Z], list_of_answers[Z]))
        Z += 1
    start_quiz()

def start_quiz():
    key = int(input("\n enter 0 to start quiz: "))
    score = 0
    If key == 0:
        for question in main_list: 
            print(question.promt) # printing the question text
            amount_of_answers = 4


            for i in list_of_keys:     ####THIS LOOP HERE#### 
                if amount_of_answers > 0:
                    print(i)
                    amount_of_answers -= 1


            answer = int(input(""))
            if answer == list_of_answers[0]:
                score += 1

makequiz()

問題 class：

class Question_template:
    def __init__(self, promt, answers, correct):
        self.promt = promt
        self.answers = answers
        self.correct = correct

Answer 1

由於您每次都從 list_of_keys 的起點進行迭代，因此您每次都會得到相同的答案。 對於問題 1，您在 0 到 4 之間迭代，對於問題 2，您再次在 0 4 之間迭代。 但是，對於問題 2，您的信息介於 4 到 8 之間。因此，您應該添加一個密鑰計數器來存儲您要查找的問題。 因此，我添加了 keyCounter，並為每個問題將其增加到 4。 除此之外，您還應該從 list_of_keys 中的那個點開始，例如 list_of_keys[keyCounter:]。

def start_quiz():
    key = int(input("\n enter 0 to start quiz: "))
    score = 0
    keyCounter = 0
    if key == 0:
        for question in main_list:
            print(question.promt) # printing the question text
            amount_of_answers = 4

            for i in list_of_keys[keyCounter:]:     ####THIS LOOP HERE####
                if amount_of_answers > 0:
                    print(i)
                    amount_of_answers -= 1
            keyCounter = keyCounter + 4