python 將字符串轉換為字典 json

Question

字符串“輸出”具有以下值：

interface Vlan364
  ip policy route-map RM_OUT
interface Vlan234
  ip policy route-map RM_OUT
interface Vlan235
  ip policy route-map RM_OUT
interface Ethernet1/2
  ip policy route-map RM_IN
interface Ethernet1/6
  ip policy route-map RM_IN

(1) 如何將其轉換為字典，因此字典“outputDict”如下所示：

{
 "interface":"Vlan364", "ip policy route-map":"RM_OUT",
 "interface":"Vlan234", "ip policy route-map":"RM_OUT",
 "interface":"Vlan235", "ip policy route-map":"RM_OUT",
 "interface":"Ethernet1/2", "ip policy route-map":"RM_IN",
 "interface":"Ethernet1/6", "ip policy route-map":"RM_IN",
}

這里的目標是識別與每個“接口”相關的“ip policy route-map”。

(2) 如何在上面的字典中找出唯一的“ip policy route-map”並將其放入列表中。 即上述字典中的 output 將是：

 route-map_list = [RM_OUT, RM_IN]

Answer 1

您可以使用正則表達式匹配關鍵字，然后使用re.finditer搜索所有匹配項，並將匹配對象放入字典列表中。

import re, json

output = """interface Vlan364
  ip policy route-map RM_OUT
interface Vlan234
  ip policy route-map RM_OUT
interface Vlan235
  ip policy route-map RM_OUT
interface Ethernet1/2
  ip policy route-map RM_IN
interface Ethernet1/6
  ip policy route-map RM_IN"""

output_list = []
route_map_list = []
REGEX_STRING = r"interface ([A-Za-z0-9//]+)[\n\r ]+ip policy route-map ([A-Z_]+)"
for match in re.finditer(REGEX_STRING,output):
    output_list.append(
        {
            "interface": match.group(1),
            "ip policy route-map": match.group(2)
        }
    )
    if match.group(2) not in route_map_list:
        route_map_list.append(match.group(2))

print(json.dumps(output_list, indent=4))
print(route_map_list)

Output：

[
    {
        "interface": "Vlan364",
        "ip policy route-map": "RM_OUT"
    },
    {
        "interface": "Vlan234",
        "ip policy route-map": "RM_OUT"
    },
    {
        "interface": "Vlan235",
        "ip policy route-map": "RM_OUT"
    },
    {
        "interface": "Ethernet1/2",
        "ip policy route-map": "RM_IN"
    },
    {
        "interface": "Ethernet1/6",
        "ip policy route-map": "RM_IN"
    }
]
['RM_OUT', 'RM_IN']