簡體   English   中英

std::any std::unique_ptr 不起作用?

[英]std::any of std::unique_ptr doesn't work?

請考慮以下 C++20 程序:

#include <any>
#include <memory>

int main() {
  std::any a;
  std::unique_ptr<int> x = std::make_unique<int>(42);
  a.emplace<std::unique_ptr<int>>(std::move(x));
}

我越來越:

test.cc: In function ‘int main()’:
test.cc:7:47: error: no matching function for call to ‘std::any::emplace<std::unique_ptr<int, std::default_delete<int> > >(std::remove_reference<std::unique_ptr<int>&>::type)’
    7 |   a.emplace<std::unique_ptr<int>>(std::move(x));
      |                                               ^
In file included from test.cc:1:
/usr/include/c++/9/any:273:7: note: candidate: ‘template<class _ValueType, class ... _Args> typename std::any::__any_constructible<std::any::_Decay<_ValueType>&, std::any::_Decay<_ValueType>, _Args&& ...>::type std::any::emplace(_Args&& ...)’
  273 |       emplace(_Args&&... __args)
      |       ^~~~~~~
/usr/include/c++/9/any:273:7: note:   template argument deduction/substitution failed:
/usr/include/c++/9/any: In substitution of ‘template<class _ValueType, class ... _Args> typename std::any::__any_constructible<std::any::_Decay<_ValueType>&, std::any::_Decay<_ValueType>, _Args&& ...>::type std::any::emplace(_Args&& ...) [with _ValueType = std::unique_ptr<int>; _Args = {std::unique_ptr<int, std::default_delete<int> >}]’:
test.cc:7:47:   required from here
/usr/include/c++/9/any:273:7: error: no type named ‘type’ in ‘struct std::enable_if<false, std::unique_ptr<int>&>’
/usr/include/c++/9/any:288:7: note: candidate: ‘template<class _ValueType, class _Up, class ... _Args> typename std::any::__any_constructible<std::any::_Decay<_ValueType>&, std::any::_Decay<_ValueType>, std::initializer_list<_Up>, _Args&& ...>::type std::any::emplace(std::initializer_list<_Up>, _Args&& ...)’
  288 |       emplace(initializer_list<_Up> __il, _Args&&... __args)
      |       ^~~~~~~
/usr/include/c++/9/any:288:7: note:   template argument deduction/substitution failed:
test.cc:7:47: note:   ‘std::unique_ptr<int>’ is not derived from ‘std::initializer_list<_Up>’
    7 |   a.emplace<std::unique_ptr<int>>(std::move(x));

有任何想法嗎?

class std::any是可復制的。 盡管它的名字,它不能包裝“任何”和所有類型。 具體來說,它不能包裝不可復制的類型。 std::unique_ptr不可復制。 std::unique_ptr不能存儲在std::any中。

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM