如何獲取結果第一行中不同值的計數

Question

我想檢查最高金額的文件的顏色和城市是否是多重的。 如果是，我想設置一點為1，如果不是，它應該是0

樣本數據：

Code doc year amount colour city
AB   123 2021 485    Red    Paris
AB   123 2021 416    Red    Paris
AB   123 2021 729    Red    London
AB   123 2021 645    Red    Bengaluru

預期 output：我想要 output 在一行

Code Doc Year Amount Colour City  Col_Mul City_Mul 
AB   123 2021 729    Red    London 0       1

數量、顏色和城市應該是最大值。

我嘗試了什么：為了獲取一行中的數據，我使用了行號並按最大數量排序，並選擇了行號為 1 的數據。 但在那之后，我對顏色和城市列使用了密集排名。 但我沒有得到預期的 output。

Answer 1

您可以使用 CROSS APPLY 並獲取數據，如下所示：

感謝@Gayani 提供測試數據。

select TOPROW.*,case when T1.colorcount > 1 THEN 1 else 0 end as Multi_color,
 case when T2.citycount > 1 THEN 1 else 0 end as Multi_city
 from
 (SELECT TOP 1 * FROM tes_firstRow
 order by amount desc) as toprow
cross apply
(
SELECT count(distinct color) from tes_firstrow WHERE doc = toprow.doc
) as t1(colorcount)
cross apply
(
SELECT count(distinct city) from tes_firstrow WHERE doc = toprow.doc
) as t2(citycount)

代碼	文檔	年	數量	顏色	城市	多色的	多城市
AB	123	2021	729	紅色的	倫敦	0	1

Answer 2

我希望這個代碼示例能幫助你。 請嘗試以下代碼，如果它對您的需要有幫助，請告訴我。 我在這里使用了臨時表。 您可以使用任何技術來構建邏輯。 CTE（公用表表達式）或派生表。

CREATE TABLE tes_firstRow
(
    Code varchar(100)
    , doc int
    , [year] int
    , amount int
    , color varchar(100)
    , City varchar(100)
)

insert into  tes_firstRow values  ('AB', 123,2021,485,'RED','PARIS')
insert into  tes_firstRow values  ('AB', 123,2021,416,'RED','PARIS')
insert into  tes_firstRow values  ('AB', 123,2021,729,'RED','LONDON')
insert into  tes_firstRow values  ('AB', 123,2021,645,'RED','BENGALURU')

SELECT 
    RANK() OVER (PARTITION BY  Code, doc,[year] ORDER BY amount DESC) AS [rank]
    ,Code
    ,doc
    ,[year]
    ,amount
    ,color
    ,City 
INTO #temp_1
FROM tes_firstRow


 SELECT 
 [#temp_1].[Code]
 ,[#temp_1].[doc]
 ,[#temp_1].[year]
 ,[#temp_1].[amount]
 ,[#temp_1].[color]
 ,[#temp_1].[City]
 , (Select COUNT(Distinct [#temp_1].[color] ) where  [#temp_1].[rank] = 1 ) as Col_Mul
 , (Select COUNT(Distinct [#temp_1].[City]) where  [#temp_1].[rank] = 1)  as City_Mul
 ,1 as City_Mul
 FROM  #temp_1 
 WHERE #temp_1.[rank] = 1
  group by   [#temp_1].[Code]
    ,[#temp_1].[doc]
    ,[#temp_1].[year]
    ,[#temp_1].[amount]
    ,[#temp_1].[color]
    ,[#temp_1].[City]
     ,[#temp_1].[rank] 

     DROP TABLE #temp_1

 Result:

Answer 3

那里有 go。 奇怪的要求...

SELECT T.Code, Doc, Year, MAX(T.Amount) Amount,
      (SELECT TOP 1 Colour FROM T as X WHERE Amount = MAX(T.Amount)) Colour,
      (SELECT TOP 1 City FROM T as X WHERE Amount = MAX(T.Amount)) City,
      CASE WHEN COUNT(DISTINCT T.Colour) > 1 THEN 1 ELSE 0 END as Col_Mul,
      CASE WHEN COUNT(DISTINCT T.City) > 1 THEN 1 ELSE 0 END as City_Mul
FROM T
GROUP BY T.Code, Doc, Year

Answer 4

我想你只想要 window 函數與條件聚合相結合：

select code, doc, year, max(amount),
       max(case when seqnum = 1 then color end) as color,
       max(case when seqnum = 1 then city end) as city,
       (case when seqnum = 1 and color_count > 1 then 1 else 0 end) as color_dup,
       (case when seqnum = 1 and city_count > 1 then 1 else 0 end) as city_dup,
from (select t.*,
             row_number() over (partition by code, doc, year order by amount desc) as seqnum,
             count(*) over (partition by code, doc, year, color) as color_count,
             count(*) over (partition by code, doc, year, city) as city_count
      from t
     ) t
group by code, doc, year;

我實際上不確定在值是否重復時是否需要1 ，因此這些值可能是倒退的。