簡體   English   中英

插入 flask SQLAlchemy 與關聯表以多對多關系插入數據時出錯

[英]Error while inseting flask SQLAlchemy Inserting Data in a Many-to-Many Relationship with Association Table

我有這樣的數據庫,關系為many2many

association_table = db.Table('association',
                             db.Column('meal_id', db.Integer, db.ForeignKey('meals.id')),
                             db.Column('order_id', db.Integer, db.ForeignKey('orders.id'))
                             )

class Order(db.Model):
    __tablename__ = 'orders'
    id = db.Column(db.Integer, primary_key=True)
    data = db.Column(db.String)
    meals = db.relationship(
        "Meals", secondary=association_table, back_populates="orders"
    )
       
class Meals(db.Model):
    __tablename__ = 'meals'
    id = db.Column(db.Integer, primary_key=True)
    title = db.Column(db.String, unique=True)
    price = db.Column(db.Float)
    orders = db.relationship(
        "Order", secondary=association_table, back_populates="meals"
    )

我嘗試將數據插入表訂單

order_to_database = Order (data='05_03_2021',
                           meals = 1
                           )

db.session.add(order_to_database)
db.session.commit()

膳食是膳食的標識。 我 go 錯誤:

我應該如何解決這個問題?

使用db.relationship時,ORM 期望meals應該是Meals實例,而不是 integer。

breakfast_meal = Meal(id=1,title='Lunch',price=9)

order_to_database = Order(data='05_03_2021')
order_to_database.meals.append(breakfast_meal)

db.session.add(order_to_database)

db.session.commit()

如果您正在使用數據庫中已有的餐點,您可以執行以下操作:

   lunch_meal = Meal.query.filter(Meal.id==10).first()
   ....
   order_to_database.meals.append(lunch_meal)
   ....
   db.session.commit()

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM