[英]How to make event loop run task concurrently?
我想在 asyncio 中同時調用兩個asyncio
,我用loop.create_task
,但我發現它實際上不是並發的。
這是我的代碼:
import asyncio
async def foo(v):
print(f"start {v}")
for i in range(5):
print(f"work in {v}")
print(f"done {v}")
def schedule_foo():
print("out start 1")
loop.create_task(foo(1))
print("out start 2")
loop.create_task(foo(2))
loop = asyncio.get_event_loop()
schedule_foo()
loop.run_forever()
這將是 output:
out start 1
out start 2
start 1
work in 1
work in 1
work in 1
work in 1
work in 1
done 1
start 2
work in 2
work in 2
work in 2
work in 2
work in 2
done 2
如您所見,主循環是異步的,但子任務實際上是同步的。
我的問題是how can I make the function run in concurrently actually
?
你忘了使用await
:
import asyncio
async def foo(v):
print(f"start {v}")
for i in range(5):
print(f"work in {v}")
await asyncio.sleep(0.1)
print(f"done {v}")
def schedule_foo():
print("out start 1")
loop.create_task(foo(1))
print("out start 2")
loop.create_task(foo(2))
loop = asyncio.get_event_loop()
schedule_foo()
loop.run_forever()
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.