計算PHP中日期/時間之間的差異

Question

我有一個Date對象（來自Pear）並且想要減去另一個Date對象以獲得以秒為單位的時間差。

我嘗試了一些東西，但第一個只是給了我幾天的差異，第二個允許我將一個固定時間轉換為unix時間戳而不是Date對象。

        $now = new Date();
        $tzone = new Date_TimeZone($timezone);
        $now->convertTZ($tzone);
        $start = strtotime($now);
        $eob = strtotime("2009/07/02 17:00"); // Always today at 17:00

        $timediff = $eob - $start;

**注意**它總是不到24小時的差異。

Answer 1

仍然給出了一些錯誤的值，但考慮到我有一個舊版本的PEAR日期，也許它適用於你或給你一個如何修復的提示:)

<pre>
<?php
  require "Date.php";

  $now = new Date();
  $target = new Date("2009-07-02 15:00:00");

  //Bring target to current timezone to compare. (From Hawaii to GMT)
  $target->setTZByID("US/Hawaii");
  $target->convertTZByID("America/Sao_Paulo");

  $diff = new Date_Span($target,$now);

  echo "Now (localtime): {$now->format("%Y-%m-%d %H:%M:%S")} \n\n";
  echo "Target (localtime): {$target->format("%Y-%m-%d %H:%M:%S")} \n\n";
  echo $diff->format("Diff: %g seconds => %C");
?>
</pre>

Answer 2

您確定Pear Date對象 - > string - > timestamp的轉換是否可靠？ 這就是在這里做的：

$start = strtotime($now);

作為替代方案，您可以根據文檔獲得這樣的時間戳

$start = $now->getTime();

Answer 3

要做到沒有梨，要找到直到17:00的秒，你可以這樣做：

$current_time = mktime (); 
$target_time = strtotime (date ('Y-m-d'. ' 17:00:00')); 
$timediff = $target_time - $current_time;

沒有測試它，但它應該做你需要的。

Answer 4

我不認為你應該將整個Date對象傳遞給strtotime。 請改用其中一個;

$start = strtotime($now->getDate());

要么

$start = $now->getTime();

Answer 5

也許有些人想要facebook的時間差。 它告訴你“一分鍾前”，或“2天前”等...這是我的代碼：

function getTimeDifferenceToNowString($timeToCompare) {

        // get current time
        $currentTime = new Date();
        $currentTimeInSeconds = strtotime($currentTime);
        $timeToCompareInSeconds = strtotime($timeToCompare);

        // get delta between $time and $currentTime
        $delta = $currentTimeInSeconds - $timeToCompareInSeconds;

        // if delta is more than 7 days print the date
        if ($delta > 60 * 60 * 24 *7 ) {
            return $timeToCompare;
        }   

        // if delta is more than 24 hours print in days
        else if ($delta > 60 * 60 *24) {
            $days = $delta / (60*60 *24);
            return $days . " days ago";
        }

        // if delta is more than 60 minutes, print in hours
        else if ($delta > 60 * 60){
            $hours = $delta / (60*60);
            return $hours . " hours ago";
        }

        // if delta is more than 60 seconds print in minutes
        else if ($delta > 60) {
            $minutes = $delta / 60;
            return $minutes . " minutes ago";
        }

        // actually for now: if it is less or equal to 60 seconds, just say it is a minute
        return "one minute ago";

    }