[英]Deserializing json as List<Object>
我有 json:
"taxLevels": [{
"code": "VAT",
"percentage": 19.0
}
]
這確實是List<TTaxLevel>
我有Model.class :
public class Model{
private final List<TTaxLevel> taxLevels;
}
和TtaxLevel.class :
@NoArgsConstructor
public class TTaxLevel {
private String code;
private Double percentage;
}
但我在這里收到錯誤:
[Resolved [org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Cannot deserialize instance of java.util.LinkedHashMap<java.lang.String,java.lang.String> out of START_ARRAY token; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of java.util.LinkedHashMap<java.lang.String,java.lang.String> out of START_ARRAY token at [Source: (PushbackInputStream); 行:36,列:19](通過參考鏈:...Model["taxLevels"])]]
我可以以某種方式強制jackson
在這里ArrayList
而不是Map
嗎? 這是一個問題。
這是反序列化代碼:
Model model = new ObjectMapper().readValue(content, Model .class);
請為您的類添加 getter/setter 方法並提供無參數構造函數。 另外你 json 不完全有效,應該是:
{
"taxLevels": [
{
"code": "VAT",
"percentage": 19.0
}
]
}
我嘗試將它放在資源文件夾中,獲取然后響應示例請求。 這是示例代碼:
@NoArgsConstructor
@AllArgsConstructor
@Getter
@Setter
class Model {
private List<TTaxLevel> taxLevels;
}
@AllArgsConstructor
@NoArgsConstructor
@Getter
@Setter
class TTaxLevel {
private String code;
private Double percentage;
}
@RequestMapping("tax-level")
@RestController
class SampleRequestBody {
private final ObjectMapper objectMapper;
SampleRequestBody(ObjectMapper objectMapper) {
this.objectMapper = objectMapper;
}
@PostMapping
public Map<String, Model> taxLevel(@RequestBody Model model) throws JsonProcessingException {
final Map<String, Model> response = new HashMap<>(1);
response.put("data", model);
return response;
}
@GetMapping
public Model getTaxLevel() throws IOException {
InputStream inputStream = new ClassPathResource("tax-level.json").getInputStream();
return objectMapper.readValue(inputStream, Model.class);
}
}
所以有兩個問題:
{
"taxLevels": [{
"code": "VAT",
"percentage": 19.0
}
]
}
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