試圖找出一種在字符串中交換字符的方法（python）

Question

我試圖在一個單詞中獲取兩個隨機字符（不是第一個或最后一個）並交換它們。 前任。 詞= wod，什么= waht。 然而，我的代碼只是用第二個隨機字母替換第一個隨機字母，而不是交換它們。 有沒有解決的辦法？

#Input
word = str(input("Please enter your word here: "))

#Processing/Functions/Output

#Only scramble if word has more than 3 letters
if len(word) > 3:
    
    #randompick picks random positions in the word 
    def randompick() :
        #Pick random positions
        pos1 = randint(1, len(word)-2) 
        pos2 = randint(1, len(word)-2)
        
        #Make sure second position isn't the same as the first
        while pos1 == pos2:
            pos2 = randint(1, len(word)-2)
        
        #assign letters to variables
        firstLetter = word[pos1]
        secondLetter = word[pos2]
        #run scramble function
        #return firstLetter, secondLetter
        
        scramble(firstLetter, secondLetter)
        
    #scramble swaps the two positions previously chosen in randompick  
    def scramble(firstLetter, secondLetter):
        scrambled_word = word.replace(firstLetter, secondLetter) #first replacement
        print (scrambled_word)
    
    #Run functions
    randompick()

else:
    print (word)

Answer 1

使用 function pop，這將記住並按索引刪除字符。 首先將字符串轉換為單詞，如此處所示。

word = ['w','o','r','d'];

print("result before swap: ", word)

randompos1 = 1
randompos2 = 2

word.insert(randompos1, word.pop(randompos2))
word.insert(randompos2, word.pop(randompos1+1))

print("result after swap: ", word)

Answer 2

您的“隨機”代碼看起來不錯，但是是的，問題出在您的替換上。 我建議使用 python 列表切片。

firstLetter = word[pos1]
secondLetter = word[pos2]

if pos1 > pos2:
    before = word[:pos1]
    between = word[pos1 + 1:pos2]
    after = word[pos2 + 1:]
    print(before + secondLetter + between + firstLetter + after)
else:
    before = word[:pos2]
    between = word[pos2 + 1:pos1]
    after = word[pos1 + 1:]
    print(before + secondLetter + between + firstLetter + after)