[英]Dynamically Building Where Clauses with Sequelize and Multiple OR Operators
[英]Dynamic where clauses Sequelize
我有以下代碼:
const { TN, TITLE, QUEUE, TYPE, SERVICE, OWNER, CUSTOMER_ID, CUSTOMER_USER_ID, CREATE_BY, create_time, ESTADO_DO_SLA } = req.query;
let query = {};
if (TN != null) query.TN = TN;
if (TITLE != null) query.TITLE = TITLE;
if (QUEUE != null) query.QUEUE = QUEUE;
if (TYPE != null) query.TYPE = TYPE;
if (SERVICE != null) query.SERVICE = SERVICE;
if (OWNER != null) query.OWNER = OWNER;
if (CUSTOMER_ID != null) query.CUSTOMER_ID = CUSTOMER_ID;
if (CUSTOMER_USER_ID != null) query.CUSTOMER_USER_ID = CUSTOMER_USER_ID;
if (CREATE_BY != null) query.CREATE_BY = CREATE_BY;
const limit = req.query.limit != null ? Number.parseInt(req.query.limit) : 1000;
const page = req.query.page != null ? (Number.parseInt(req.query.page) * limit) - limit : 0;
const tickets = await ViewSLA.findAll({
raw: true,
offset: page,
limit: limit,
where: query
});
關鍵是, where部分正在工作,但只有在值相等時才匹配,但我想在某些參數中做一些Op.like並保持其他可選。
例如,匹配 TN(票號)參數的確切值是有意義的,但我想通過 TITLE 參數進行過濾,如果它被告知,在 where 子句中使用like 。
那可能嗎?
我剛剛找到了一種方法:
const { TN, TITLE, QUEUE, TYPE, SERVICE, OWNER, CUSTOMER_ID, CUSTOMER_USER_ID, CREATE_BY, create_time, ESTADO_DO_SLA } = req.query;
let query = {};
if (TN != null) query.TN = TN;
if (TITLE != null) query.TITLE = {
[Op.like]: `%${TITLE}%`
};
if (QUEUE != null) query.QUEUE = QUEUE;
if (TYPE != null) query.TYPE = TYPE;
if (SERVICE != null) query.SERVICE = SERVICE;
if (OWNER != null) query.OWNER = OWNER;
if (CUSTOMER_ID != null) query.CUSTOMER_ID = CUSTOMER_ID;
if (CUSTOMER_USER_ID != null) query.CUSTOMER_USER_ID = CUSTOMER_USER_ID;
if (CREATE_BY != null) query.CREATE_BY = CREATE_BY;
if (ESTADO_DO_SLA != null) query.ESTADO_DO_SLA = ESTADO_DO_SLA;
const limit = req.query.limit != null ? Number.parseInt(req.query.limit) : countTickets;
const page = req.query.page != null ? (Number.parseInt(req.query.page) * limit) - limit : 0;
const tickets = await ViewSLA.findAll({
raw: true,
offset: page,
limit: limit,
where: query
});
像魅力一樣工作。
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