[英]Printing 2D array elements within a function is causing a segmentation fault
我創建了一個二維數組,每行接收 1-60 之間的 6 個隨機不同值。
#define QTE 50
#define NUM 6
void mostrar();
int main(void)
{
int sorteios[QTE][NUM], repeticao[61] = {};
srand(time(NULL));
for (int i = 1; i < QTE; i++)
{
for (int j = 0; j < 6; j++)
{
int gerado = rand() % 60 + 1;
for (int k = j; k > 0; k--)
{
if (j == 0)
{
break;
}
while (gerado == sorteios[i][k])
{
gerado = rand() % 60 + 1;
}
}
sorteios[i][j] = gerado;
int aleatorio = sorteios[i][j];
repeticao[aleatorio] += 1;
}
printf("Sequência %04d:\t %02d\t%02d\t%02d\t%02d\t%02d\t%02d\n", i, sorteios[i][0], sorteios[i][1], sorteios[i][2], sorteios[i][3], sorteios[i][4], sorteios[i][5]);
}
mostrar(sorteios[QTE][NUM]);
}
如果main
function 中有一個 for 循環,但使用 function 執行導致分段錯誤(核心轉儲),則此代碼本身正在工作。
void mostrar(int *array[QTE][NUM])
{
printf("Mostrando..\n");
for (int p = 0; p < QTE; p++)
{
printf("Sequência %04d:\t %02d\t%02d\t%02d\t%02d\t%02d\t%02d\n", p, *array[p][0], *array[p][1], *array[p][2], *array[p][3], *array[p][4], *array[p][5]);
}
}
控制台結果的一部分..
...
Sequência 0043: 35 59 08 31 16 40
Sequência 0044: 26 47 27 52 32 08
Sequência 0045: 35 34 26 35 31 14
Sequência 0046: 07 44 13 22 35 46
Sequência 0047: 50 17 16 53 49 29
Sequência 0048: 27 39 37 50 10 44
Sequência 0049: 29 35 30 55 18 53
Mostrando..
Segmentation fault (core dumped)
除了將數組傳遞給 function 的方式(已在評論中討論)之外,您的代碼中還有一些其他問題,這里是一個更正版本,其中包含需要修復的注釋:
#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#define QTE 50
#define NUM 6
// if you want the access the array, jut use that as an argument, no pointer needed
void mostrar(int array[][NUM])
{
printf("Mostrando..\n");
for (int p = 0; p < QTE; p++)
{
// correcting the dereference to match the argument...
printf("Sequência %04d:\t %02d\t%02d\t%02d\t%02d\t%02d\t%02d\n", p, array[p][0], array[p][1], array[p][2], array[p][3], array[p][4], array[p][5]);
}
}
int main(void)
{
int sorteios[QTE][NUM], repeticao[61] = {0};
srand(time(NULL));
// beginning at index 1 would leave the first index empty, also messing up the
// indexing in the function, so start at index 0
for (int i = 0; i < QTE; i++)
{
for (int j = 0; j < 6; j++)
{
int gerado = rand() % 60 + 1;
for (int k = j; k > 0; k--)
{
if (j == 0)
{
break;
}
while (gerado == sorteios[i][k])
{
gerado = rand() % 60 + 1;
}
}
sorteios[i][j] = gerado;
int aleatorio = sorteios[i][j];
repeticao[aleatorio] += 1;
}
}
// pass only the array, if you include indexes you are just passing an element
// of the array, and sorteios[QTE][NUM] would be outside of the bounds of the array
// and wouldn't match the original function argument either
mostrar(sorteios);
}
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