從列表內部分離字典值

Question

所以目前我正在從 who.is 中提取數據，大約有 2000 個鏈接，所以我只是用 function 對其進行了迭代，但是 output 是這樣的：

[{"email":"email@email.com", "Phone_no.":"+123456789", "more data":"more data", "even more data":"even more data"},
{"email":"email@email.com", "Phone_no.":"+123456789", "more data":"more data", "even more data":"even more data"},
{"email":"email@email.com", "Phone_no.":"+123456789", "more data":"more data", "even more data":"even more data"}]

所需的 output 有點像：

["email@email.com","email@email.com","email@email.com"],["+123456789","+123456789","+123456789"]

Answer 1

您應該迭代列表的每個字典。

這看起來像這樣：

email = []
phone_no = []

for d in data:
   for key,value in d:
      if(str(key) == 'email'):
         email.append(value)
      elif(str(key) == 'Phone_no.'):
         phone_no.append(value)
      else:
         pass

所以你有 email 列表和所有 email 地址和 phone_no 所有電話號碼

Answer 2

假設您的數據位於名為data的變量中：

emails = [d['email'] for d in data]
phone_numbers = [d['Phone_no.'] for d in data]

print(emails)
print(phone_numbers)

Output：

['email@email.com', 'email@email.com', 'email@email.com']
['+123456789', '+123456789', '+123456789']