[英]Why is this program going into an infinite loop after the first scanf?
我試圖讓程序允許用戶輸入一個數字,然后讓計算機告訴用戶這個數字是太小、太大還是等於隨機生成的數字。 提示和輸入工作,但它在第一次 scanf 后卡住了。
我認為它與 scanf 而不是條件有關,因為我添加了 printf("Testing stop point") 並且不會打印到用戶的屏幕上。 我究竟做錯了什么?
#include <stdio.h>
#include <stdbool.h>
#include <time.h>
#include <stdlib.h>
int main()
{
//Generate a random number
int n = 1;
int count = 0;
int randomNumber;
srand(time(NULL));
for (int i = 1; i <= n; i++)
{
randomNumber = rand() % 101;
}
printf("Guess a number between 1 - 100: ");
int input;
scanf("%d\n",&input);
printf("Testing stopping point");
do
{
if (input > randomNumber)
{
count +=1;
printf("Too large!Try again: ");
getchar();
}else if (input < randomNumber)
{
count += 1;
printf("Too small!Try again: ");
getchar();
}
}while (input != randomNumber);
if(input == randomNumber)
{
count +=1;
printf("Correct!\n");
printf("You guessed %d times\n", count);
return 0;
}
}
您必須刪除scanf
中的\n
,嘗試如下:
#include <stdio.h>
#include <stdbool.h>
#include <time.h>
#include <stdlib.h>
int main()
{
//Generate a random number
int count = 0;
int randomNumber;
srand(time(NULL));
randomNumber = (rand() % 101)+1;
int input=-1;
while (input != randomNumber)
{
printf("Guess a number between 1 - 100: ");
scanf("%d",&input);
if (input > randomNumber)
{
count +=1;
printf("Too large!Try again: ");
}else if (input < randomNumber)
{
count += 1;
printf("Too small!Try again: ");
}
}
if(input == randomNumber)
{
count +=1;
printf("Correct!\n");
printf("You guessed %d times\n", count);
}
return 0;
}
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