[英]mysql update json field getting quoted
我將以下 json 結構存儲到 mysql
{
"somefield": "0",
"date": "2020-12-01",
"caption": null,
"field": [
{
"id_type1": "5192"
},
{
"id_type2": "3285"
},
{
"id_type2": "3638"
},
{
"id_type2": "3750"
},
{
"id_type2": "3760"
},
{
"id_type1": "3161"
},
{
"id_type1": "1044"
}
],
"question": "",
"people": [],
"title": ""
}
當我提交一個表單時,我想按名稱檢索非空值,然后更新 json 字段
假設我提交了 2 個字段, date
和field
字段
[{"id_type1":5192},{"id_type2":3285},{"id_type2":3638},{"id_type2":3750},{"id_type2":3760},{"id_type1":3161},{"id_type1":1044},{"id_type1":8081}]
日期
'2021-04-02'
我想用這些值更新 json 字段
UPDATE table
SET
json_champ = JSON_SET(json_champ, '$."field"', '[{"id_type1":5192},{"id_type2":3285},{"id_type2":3638},{"id_type2":3750},{"id_type2":3760},{"id_type1":3161},{"id_type1":1044},{"id_type1":8081}]', '$."date"', '2020-12-01')
WHERE id = '52907';
日期一切正常,但字段被轉義
"field": "[{\"id_type1\":5192},{\"id_type2\":3285},{\"id_type2\":3638},{\"id_type2\":3750},{\"id_type2\":3760},{\"id_type1\":3161},{\"id_type1\":1044},{\"id_type1\":8081}]"
預期的
"field": [{"id_type1":5192},{"id_type2":3285},{"id_type2":3638},{"id_type2":3750},{"id_type2":3760},{"id_type1":3161},{"id_type1":1044},{"id_type1":8081}]
如果我將預期的 output 直接粘貼到 PMA 中,它會按預期工作
粘貼
{
"somefield": "0",
"date": "2020-12-01",
"caption": null,
"field": [{"id_type1":5192},{"id_type2":3285},{"id_type2":3638},{"id_type2":3750},{"id_type2":3760},{"id_type1":3161},{"id_type1":1044},{"id_type1":8081}],
"question": "",
"people": [],
"title": ""
}
生成的 sql 查詢
<?php
$sqlUpdate = " UPDATE table
SET
json_champ = JSON_SET(json_champ, '$."field"', '".json_encode($fieldValues, , JSON_HEX_TAG | JSON_HEX_AMP | JSON_HEX_APOS | JSON_HEX_QUOT)."', '$."date"', '2020-12-01')
WHERE id = '".$id."'";
據我所知,唯一的區別是在 json 的開頭添加字段,然后將字符串插入表中?
$json_string = '[{"id_type1":5192},{"id_type2":3285},{"id_type2":3638},{"id_type2":3750},{"id_type2":3760},{"id_type1":3161},{"id_type1":1044}]';
$ammended_string = json_encode(['field' => json_decode($json_string)]);
$sqlUpdate = " UPDATE table
SET
json_champ = '".$ammended_string ."'
WHERE id = '".$id."'";
如果我錯了,請糾正我,但認為你可能有點過於復雜了。
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