mysql 按某些條件排序且不區分大小寫

Question

我想排序

“特殊字符-數字-字母-其他-空格”

並使用此查詢

SELECT title FROM table ORDER BY (case when ASCII(SUBSTRING(title, 1)) = 0 then 9 when (ASCII(SUBSTRING(title, 1)) >= 33 and ASCII(SUBSTRING(title, 1)) <= 47) then 1 when (ASCII(SUBSTRING(title, 1)) >= 58 and ASCII(SUBSTRING(title, 1)) <= 64) then 2 when (ASCII(SUBSTRING(title, 1)) >= 91 and ASCII(SUBSTRING(title, 1)) <= 96) then 3 when (ASCII(SUBSTRING(title, 1)) >= 123 and ASCII(SUBSTRING(title, 1)) <= 126) then 4 when (ASCII(SUBSTRING(title, 1)) >= 48 and ASCII(SUBSTRING(title, 1)) <= 57) then 5 when ASCII(SUBSTRING(title, 1)) > 128 then 7 when ASCII(SUBSTRING(title,1)) = 32 then 8 else 6 end ),binary(title)";

我有這個查詢想要的結果。

但有一件事，

字母順序結果是（A，B，C，a，b，c）

我想要結果為 (A, a, B, b, C, c)

我怎么能得到那個？

Answer 1

做你想做的事是非常困難的。 我建議稍微放松一下你的約束，並且只遵循 ascii 順序，除了將空格更改為一些高字符：

ORDER BY REPLACE(title,' ',CONVERT(_utf32 0x10FFFF USING utf8mb4)),BINARY(title);