使用 JavaScript，如何在子 object 中使用多個條件過濾對象數組

Question

我想得到所有退回產品“2”的客戶：

 // Note that in production this array is much longer const customers = [ { "customerId": "1", "products": [ { "productId": "1", "status": "purchased" }, { "productId": "2", "status": "purchased" } ] }, { "customerId": "2", "products": [ { "productId": "1", "status": "purchased" }, { "productId": "2", "status": "returned" } ], } ] const returns = customers.filter((customer) => customer.products.some((product) => product.productId === "2" && product.status === "returned") ); console.log(returns);

我認為我使用filter會起作用 - 但我猜 some() 不適用於多個標准？ 還是我做錯了什么？ 或者，還有更好的方法？

Answer 1

您的條件product.productId === "2" && product.status === "returned"只匹配一個 object

如果 productId 為“2”且狀態為“returned” ，則與返回的最后一個 object 匹配。

如果您只想要 ID 為 '2' 的產品，那么它應該是product.productId === "2"

希望這是有道理的

Answer 2

嘗試對產品使用一些function。

 const customers = [{ "customerId": "1", "products": [{ "productId": "1", "status": "purchased" }, { "productId": "2", "status": "purchased" } ] }, { "customerId": "2", "products": [{ "productId": "1", "status": "purchased" }, { "productId": "2", "status": "returned" } ], } ] const returns = customers.filter((customer) => customer.products.some((product) => product.productId === "2" && product.status === "returned")) console.log(returns);