正則表達式：匹配字符串后跟點/逗號后跟空格

Question

我想把我的text = "hello this is me, and only me. be carefull from 911. "

into: text = "hello this is me,<break></break> and only me.<break></break> be carefull from 911. "

僅適用於后跟點或逗號而不是數字的字符串。

我試過這個表達式： r"\w+([.,])+\s*"但它也匹配數字。

Answer 1

您可以使用

re.sub(r'([^\W\d_][.,])(\s+)', r'\1<break></break>\2', text)

請參閱正則表達式演示。

詳情：

• ([^\W\d_][.,]) - 第 1 組（ \1 ）：任何字母，然后是 a . 或,
• (\s+) - 第 2 組 ( \2 )：一個或多個空白字符。

請參閱Python 演示：

import re
text = "hello this is me,<break></break> and only me.<break></break> be carefull from 911. "
print(re.sub(r'([^\W\d_][.,])(\s+)', r'\1<break></break>\2', text))
# => hello this is me,<break></break> and only me.<break></break> be carefull from 911.