根據 object 屬性和條件刪除數組中的 object

Question

我有可以用另一個對象數組刪除的對象數組，即

data = [ 
  {"id": 1, name: "a", qty: 1},
  {"id": 2, name: "b", qty: 1},
  {"id": 2, name: "b", qty: 1, bonusFromId: 3},
  {"id": 2, name: "b", qty: 1, bonusFromId: 1},
  {"id": 3, name: "c", qty: 1}
]

我想拼接 id 與 bonusFromId 相同的數組

temp = [ 
  {"id": 1, name: "a", qty: 1},
  {"id": 3, name: "b", qty: 1}
]

我期望的價值是

[ 
  {"id": 1, name: "a", qty: 1}
  {"id": 2, name: "b", qty: 1}
  {"id": 3, name: "c", qty: 1}
]

我試過了，但沒有用

 data.forEach(x => {
  let index = temp.filter(y => x.bonusFromId == y.id).map((item) => { return item.id}).indexOf(x.id)
  arr.splice(index, 1)
 })

Answer 1

 const data = [ {"id": 1, name: "a", qty: 1}, {"id": 2, name: "b", qty: 1}, {"id": 2, name: "b", qty: 1, bonusFromId: 3}, {"id": 2, name: "b", qty: 1, bonusFromId: 1}, {"id": 3, name: "c", qty: 1} ] const temp = [ {"id": 1, name: "a", qty: 1}, {"id": 3, name: "b", qty: 1} ] temp.forEach(t=>{ let find = data.find(e => e.bonusFromId == t.id) // find t.id in data.bonusFromId let index = data.indexOf(find); // get index of item in array data data.splice(index, 1); // splice it console.log(index) }) console.log(data)

 .as-console-wrapper{ min-height: 100%}

或如評論中所述：

 const data = [ {"id": 1, name: "a", qty: 1}, {"id": 2, name: "b", qty: 1}, {"id": 2, name: "b", qty: 1, bonusFromId: 3}, {"id": 2, name: "b", qty: 1, bonusFromId: 1}, {"id": 3, name: "c", qty: 1} ] const temp = [ {"id": 1, name: "a", qty: 1}, {"id": 3, name: "b", qty: 1} ] temp.forEach(t=>{ let find = data.findIndex(e => e.bonusFromId == t.id) find >= 0? data.splice(find, 1): null console.log(find) }) console.log(data)

 .as-console-wrapper{ min-height: 100%}