C++ 模板 ID 與任何模板都不匹配

Question

嗨，我正在嘗試重載 << 運算符

#include <iostream>
using namespace std;

template <class T, class U>
class Couple
{
public:
    T cle;
    U valeur;

public:
    Couple();
    Couple(T, U);
    friend ostream &operator<<<>(ostream &, Couple<T, U>);
};
template <class T, class U>
ostream &operator<<(ostream &os, Couple<T, U> Cpl)
{
    os << Cpl.cle << " : " << Cpl.valeur << endl;
    return os;
}

但它給了我這個錯誤我在互聯網上嘗試了一切

在 Couple.cpp:2 包含的文件中，來自 main.cpp:2：Couple.h：在 'class Couple<int, std::__cxx11::basic_string >' 的實例化中：main.cpp:7:28：需要來自這里 Couple.h:14:21: error: template-id 'operator<< <>' for 'std::ostream& operator<<(std::ostream&, Couple<int, std::__cxx11::basic_string >)'不匹配任何模板聲明

Answer 1

需要提前聲明算子模板。 例如

// forward declaration for class template
template <class T, class U>
class Couple;
// declaration
template <class T, class U>
ostream &operator<<(ostream &os, Couple<T, U> Cpl);

template <class T, class U>
class Couple
{
    ...
    // friend declaration
    friend ostream &operator<<<>(ostream &, Couple<T, U>);
};

// definition
template <class T, class U>
ostream &operator<<(ostream &os, Couple<T, U> Cpl)
{
    ...
}