有沒有辦法跳過空、空白或值？ 使用 urlfetchapp 和/或在我的數據范圍中時的單元格？ 或其他解決我的問題的方法？

Question

下面的這段代碼是從 web 中逐部分復制粘貼的，它確實有效，在一些幫助下，我能夠在一定程度上實現我的這個項目的一個目標。 問題是這樣的：我有一個帶有數據的谷歌表，我正在使用 UrlFetchApp 將圖像附加到電子郵件中，但是當我的腳本運行為空、空白或值時。 細胞停止運行並破裂？ 有什么辦法可以防止這種情況。 我是一個完全的新手，不知道。 我在網上搜索並確實找到了此信息... 如何使用 MailApp.SendEmail 跳過空白單元格？ 我試圖將它應用於我的情況，但無法。

 if (emailAddress.match('@')  === null){
       continue;  // skip this iteration of the loop and go to the next one
    }; 

我嘗試將其更改為我的項目情況...

if (image01.match('jpg')  === null){
       continue;  // skip this iteration of the loop and go to the next one
    };  

但不幸的是，'image01.match' 不是 function（我知道你們所有的編碼人員現在都在笑）所以我又嘗試了一些東西，但也沒有用....

if ((row[3]).match('jpg')  === null){
       continue;  // skip this iteration of the loop and go to the next one
    };  

所以這里是完整的代碼......非常感謝任何幫助或建議，謝謝！

function emailImage(){
 var EMAIL_SENT = "EMAIL_SENT";

   var sheet = SpreadsheetApp.getActiveSheet();
    var startRow = 2;
    var numRows = sheet.getLastRow();
   // Fetch the range of cells
   var dataRange = sheet.getRange(startRow, 1, numRows, 24)  
   var data = dataRange.getValues(); 

  for (var i = 0; i < data.length; ++i) {
    var row = data[i];
    var emailAddress = row[0];  // First column
    var subject = row[1];       // Second column
    var message = row[2];       // Third column
    var image01 = UrlFetchApp.fetch(row[3]).getBlob();
    var image02 = UrlFetchApp.fetch(row[4]).getBlob();
    var image03 = UrlFetchApp.fetch(row[5]).getBlob();


var emailSent = row[23];     // 
    if (emailSent != EMAIL_SENT) {  // Prevents sending duplicates
      MailApp.sendEmail(emailAddress, subject, message, {attachments: [image01, image02, image03]});
      sheet.getRange(startRow + i, 24).setValue(EMAIL_SENT);
      // Make sure the cell is updated right away in case the script is interrupted
      SpreadsheetApp.flush();
    }
  }
}

Answer 1

嘗試這個：

function emailImage() {
  const sh = SpreadsheetApp.getActiveSheet();
  const sr = 2;
  const rg = sh.getRange(sr, 1, sh.getLastRow() - sr + 1, 24);//your previous code was not calculating the number of rows properly so you were trying run the code in rows that probably did not have any data.
  const data = rg.getValues();
  for (let i = 0; i < data.length; ++i) {
    let row = data[i];
    let emailAddress = row[0];  // First column
    let subject = row[1];       // Second column
    let message = row[2];       // Third column
    let image01 = UrlFetchApp.fetch(row[3]).getBlob();
    let image02 = UrlFetchApp.fetch(row[4]).getBlob();
    let image03 = UrlFetchApp.fetch(row[5]).getBlob();
    let emailSent = row[23];   
    if (emailAddress && subject && message && image01 && image02 && image03 && emailSent != "EMAIL_SENT") {  // Prevents sending duplicates and emails without all of the data being present
      MailApp.sendEmail(emailAddress, subject, message, { attachments: [image01, image02, image03] });
      sh.getRange(sr + i, 24).setValue(EMAIL_SENT);
      SpreadsheetApp.flush();
    }
  }
}

試試這種方式：

function emailImage() {
  const sh = SpreadsheetApp.getActiveSheet();
  const sr = 2;
  const rg = sh.getRange(sr, 1, sh.getLastRow() - sr + 1, 24)
  const data = rg.getValues();
  for (let i = 0; i < data.length; ++i) {
    let row = data[i];
    let emailAddress = row[0];  // First column
    let subject = row[1];       // Second column
    let message = row[2];       // Third column
    let options ={attachments:[]};
    let image01 = UrlFetchApp.fetch(row[3]).getBlob();
    if(image01)options.attachments.push(image01);
    let image02 = UrlFetchApp.fetch(row[4]).getBlob();
    if(image02)options.attachments.push(image02);
    let image03 = UrlFetchApp.fetch(row[5]).getBlob();
    if(image03)options.attachments.push(image03);
    let emailSent = row[23];   
    if (emailAddress && subject && message && emailSent != "EMAIL_SENT") {  // Prevents sending duplicates
      MailApp.sendEmail(emailAddress, subject, message, options);
      sh.getRange(sr + i, 24).setValue(EMAIL_SENT);
      SpreadsheetApp.flush();
    }
  }
}

你也可以這樣嘗試：

function emailImage() {
  const sh = SpreadsheetApp.getActiveSheet();
  const sr = 2;
  const rg = sh.getRange(sr, 1, sh.getLastRow() - sr + 1, 24)
  const data = rg.getValues();
  for (let i = 0; i < data.length; ++i) {
    let row = data[i];
    let emailAddress = row[0];  // First column
    let subject = row[1];       // Second column
    let message = row[2];       // Third column
    let options ={attachments:[]};
    let urls=[row[3],row[4],row[5]].filter(e => e != '');

前一行刪除了空白的 url，下一行只推送返回非 null 的圖像 blob。 因此，您可以使用盡可能多的圖像來保存列，或者您可以將所有 url 放入一個單元格中，並用說 control enter 將它們分開，在它們之間放置 '\n' 然后你可以使用。 類似於 row[3].toString().split('\n').filter(e=>e)...等

    urls.forEach(u=>{let img = UrlFetchApp.fetch(u).getBlob();if(img)options.attachments.push(img);});
    let emailSent = row[23];   
    if (emailAddress && subject && message && emailSent != "EMAIL_SENT") {  // Prevents sending duplicates
      MailApp.sendEmail(emailAddress, subject, message, options);
      sh.getRange(sr + i, 24).setValue(EMAIL_SENT);
      SpreadsheetApp.flush();
    }
  }
}

一般來說，我最好的代碼在我通過幾次迭代 go 之前不會向我展示。

Answer 2

blob是 object 類型，您不能直接.match()它。

相反，像這樣使用try-catch ：

try{
    var image01 = UrlFetchApp.fetch(row[3].toString()).getBlob();

    console.log(image01.getContentType());  //should be image/png.
    console.log(image01);                   //should be {}

  }
  catch(Exception)
  {
    console.log("Link error!");
  }

如果鏈接中有任何錯誤， catch會處理它。 否則，您可以在try部分發送郵件。

希望這會幫助你。 如果這不是你想要的，那么我道歉。

Answer 3

這似乎有效..多種努力的結合。 謝謝 MetaMan.. 我要先測試一下....

function emailImage() {
 var EMAIL_SENT = "EMAIL_SENT";

   var sheet = SpreadsheetApp.getActiveSheet();
    var startRow = 2;
    var numRows = sheet.getLastRow();
   // Fetch the range of cells
   var dataRange = sheet.getRange(startRow, 1, numRows, 24)  
   var data = dataRange.getValues(); 

  for (let i = 0; i < data.length; ++i) {
    let row = data[i];
    let emailAddress = row[0];  // First column
    let subject = row[1];       // Second column
    let message = row[2];       // Third column
    let options ={attachments:[]};
    let urls=[row[3],row[4],row[5]].filter(e => e != '');
    urls.forEach(u=>{let img = UrlFetchApp.fetch(u).getBlob();if(img)options.attachments.push(img);});
    let emailSent = row[23];   
    if (emailAddress && subject && message && emailSent != "EMAIL_SENT") {  // Prevents sending duplicates
      MailApp.sendEmail(emailAddress, subject, message, options);
      sh.getRange(sr + i, 24).setValue(EMAIL_SENT);
      SpreadsheetApp.flush();
    }
  }
}