如何在 c++ 中獲取字符串的特定部分？

Question

我有以下字符串，我需要取出 id (68890) 類似日期 (01/14/2005)

CString strsample = "This is demo to capture the details of date (01/14/2005) parent id (68890) read (0)"  

CString strsample =   This is demo (Sample,Application) to capture the details of date (01/14/2005) parent id (68890) read (0) Total(%5)

我如何在 C++ 中實現這一點，是否有任何方法可以在正則表達式或任何可用功能中執行。

Answer 1

使用標准庫最簡單的方法是使用std::sscanf ：

#include <iostream>
#include <string>
#include <cstdio>
#include <ctime>
#include <iomanip>

int main()
{
    std::string s;

    while (std::getline(std::cin, s)) {
        std::tm t{};
        int id, read;
        auto c = std::sscanf(s.c_str(), 
            "This is demo to capture the details of date (%d/%d/%d) parent id (%d) read (%d)",
            &t.tm_mon,
            &t.tm_mday,
            &t.tm_year,
            &id,
            &read);

        --t.tm_mon;
        t.tm_year -= 1900;

        std::mktime(&t);
        if (c == 5) {
            std::cout << std::put_time(&t, "%F") 
                << " id: " << id 
                << " read: " << read
                << '\n';
        } else {
            std::cerr << "Invalid input\n";
        }
    }

    return 0;
}

https://godbolt.org/z/4P5GY4afz