如何合並多個帶有id的數組

Question

大家好，我在分組數組時遇到了一些問題我有一個像這樣的 object 數組

var result= [
        {
            "user_id": 3,
            "type_id": 1,
            "total": 24,
            "correct": 17,
            "wrong": 7,
            "not_attempt": 0,
            "standard": "9",
            "gender": "Male",
            "name": "Mohammed"
        },
        {
            "user_id": 4,
            "type_id": 1,
            "total": 24,
            "correct": 4,
            "wrong": 20,
            "not_attempt": 0,
            "standard": "7",
            "gender": "Male",
            "name": "Alex"
        },
        {
            "user_id": 3,
            "type_id": 3,
            "total": 20,
            "correct": 9,
            "wrong": 11,
            "not_attempt": 0,
            "name": "Mohammed",
            "standard": "9",
            "gender": "Male"
        },
        {
            "user_id": 4,
            "type_id": 3,
            "total": 20,
            "correct": 4,
            "wrong": 16,
            "not_attempt": 0,
            "name": "Alex",
            "standard": "7",
            "gender": "Male"
        },
        {
            "user_id": 3,
            "type_id": 4,
            "total": 20,
            "correct": 2,
            "wrong": 18,
            "not_attempt": 0,
            "name": "Mohammed",
            "standard": "9",
            "gender": "Male"
        },
        {
            "user_id": 4,
            "type_id": 4,
            "total": 20,
            "correct": 5,
            "wrong": 15,
            "not_attempt": 0,
            "name": "Alex",
            "standard": "7",
            "gender": "Male"
        },
        {
            "user_id": 3,
            "type_id": 5,
            "total": 72,
            "correct": 39,
            "wrong": 33,
            "not_attempt": 0,
            "name": "Mohammed",
            "standard": "9",
            "gender": "Male"
        },
        {
            "user_id": 4,
            "type_id": 5,
            "total": 72,
            "correct": 37,
            "wrong": 35,
            "not_attempt": 0,
            "name": "Alex",
            "standard": "7",
            "gender": "Male"
        },
        {
            "user_id": 3,
            "type_id": 6,
            "total": 25,
            "correct": 0,
            "wrong": 25,
            "not_attempt": 0,
            "name": "Mohammed",
            "standard": "9",
            "gender": "Male"
        },
        {
            "user_id": 4,
            "type_id": 6,
            "total": 25,
            "correct": 0,
            "wrong": 25,
            "not_attempt": 0,
            "name": "Alex",
            "standard": "7",
            "gender": "Male"
        },
        {
            "user_id": 3,
            "type_id": 7,
            "total": 72,
            "correct": 39,
            "wrong": 33,
            "not_attempt": 0,
            "name": "Mohammed",
            "standard": "9",
            "gender": "Male"
        },
        {
            "user_id": 4,
            "type_id": 7,
            "total": 72,
            "correct": 40,
            "wrong": 32,
            "not_attempt": 0,
            "name": "Alex",
            "standard": "7",
            "gender": "Male"
        },
        {
            "user_id": 3,
            "type_id": 8,
            "total": 12,
            "correct": 6,
            "wrong": 6,
            "not_attempt": 0,
            "name": "Mohammed",
            "standard": "9",
            "gender": "Male"
        },
        {
            "user_id": 4,
            "type_id": 8,
            "total": 12,
            "correct": 2,
            "wrong": 10,
            "not_attempt": 0,
            "name": "Alex",
            "standard": "7",
            "gender": "Male"
        }
    ]

我想按這個 object 按 user_id 和 type_id 和他們的分數分組我想要一個如下所示的結果

[
    {
         "user_id": 3,
         "gender": "Male",
        "name": "Mohammed",
        "standard": "9",
        "va":17,
        "na":9,
        "ca":2,
        "sa":39,
        "ma":0,
        "cl":39,
        "ra":6
    },
    {
         "user_id": 4,
         "gender": "Male",
        "name": "Alex",
        "standard": "7",
        "va":4,
        "na":4,
        "ca":5,
        "sa":37,
        "ma":0,
        "cl":40,
        "ra":2
    }
]

如果 user_id = 3 & type_id = 1 那么我希望像 va 一樣添加新密鑰，並且該 type_if 的正確分數將添加到該新密鑰相同的方法將適用於他們的 user_id 的所有 type_id，我嘗試了下面的代碼，但我不是得到我想要的結果

var newresult = result.reduce(function(results, org) {
                    (results[org.user_id] = results[org.user_id] || []).push(org);
                    return results;
                  }, {})

Answer 1

我不知道如何計算分數 (va, na, ca, sa, ...)

但是你可以通過這種方式做到這一點

function initializeUserObject(row) {
  const { user_id, gender, name, standard } = row;
  return { user_id, gender, name, standard };
}
function calculateScore(row) {
  const userScoreObject = {};
  // TODO : calculate score
  return userScoreObject;
}
const userMap = {}
result.forEach(row => {
  if (!(row.user_id in userMap)) {
    userMap[row.user_id] = initiailzeUserObject(row);
  }
  Object.assign(userMap[row.user_id], calculateScore(row));
})
const newResult = Object.values(userMap);

或減少

const newResult = Object.values(result.reduce((userMap, cur) => {
  userMap[cur.user_id] = Object.assign(userMap[cur.user_id] || {}, cur)
}, {}));
// you should calculate score after merge

Answer 2

一般來說，您可以使用與以下相同的代碼

var newresult = result.reduce(function(results, org) {
                    (results[org.user_id] = results[org.user_id] || []).push(org);
                    return results;
                  }, {})

對於僅包含 type_id 1 的列表，請嘗試以下操作

var type_id = 1;    

var newresult = result.reduce(function(results, org) {
                            if(org.type_id == type_id && org.type_id != 'undefined' )
                                (results[org.user_id] = results[org.user_id] || []).push(org);
                            return results;
                      }, {});

請注意，這將獲得 object 鍵，它們出現在結果變量 object 中，然后您可以循環並計算新結果的分數。