RandomAccessFile.write不寫我告訴的內容

Question

大家好。 我正在從一個sql格式的文件讀取到另一個，而中間的兩個字節已損壞，並且我認為這是我沒有做的准備或保護措施。

數據損壞示例：

//From the file that is read from. added ** to emphasize the corrupted byte
insert into viruses (virusSig,virusHash) values (
X'579fdc569b170419e15750f0feb360aa9c58d8**90**eede50def97ee7cb03b9e905',
X'ee002fe5');

//From the file that is written to. added ** to emphasize the corrupted byte
insert into changes (filepath,loc,dat,vir,hash) values (
'E:\MyDocs\intel\antivirus\RandomFiles\0\2\5\11\24\49\EG1AxxeJSr.data',
243540,
X'9f4246ff8c73c5a5b470cab8c38416929c4eacc1e0021d5ac1fdbb88145d3e6f',
X'579fdc569b170419e15750f0feb360aa9c58d8**3f**eede50def97ee7cb03b9e905',
X'6546dd27');

讀取/寫入的代碼：

public static void insertViruses(FileLocation[] locations, byte[][] viruses, String logpath)
{
    int numViruses = viruses.length;
    int virusLength = GenerateRandomCorpus.virusSignatureLengthInBytes;

    try{


        for (int i = 0; i < numViruses; i++)
        {   
            FileOutputStream logwriter = new FileOutputStream(logpath, true);

            // Prep to copy section
            int locationOfChange = locations[i].index;
            String filepathToChange = locations[i].filepath;
            File checkIfBackupExists = new File(filepathToChange + ".bak");
            if (!checkIfBackupExists.exists())
                copyFile(filepathToChange, filepathToChange + ".bak");
            copyFile(filepathToChange, filepathToChange + ".tmp");

            RandomAccessFile x = new RandomAccessFile(filepathToChange, "rw");
            x.seek(locationOfChange);

            // Copy section into byte array to write in log
            byte[] removedSection = new byte[virusLength];
            x.read(removedSection, 0, virusLength);
            if (GenerateRandomCorpus.dbg)
                System.out.println(filepathToChange + ":" + locationOfChange);
            x.close();

            // Write changes to log
            byte[] removedSectionConvertedToHexString = StringUtils.getHexString(removedSection).getBytes();
            byte[] virusConvertedToHexString = StringUtils.getHexString(viruses[i]).getBytes();
            byte[] hashConvertedToHexString = StringUtils.getHexString(GenerateRandomViruses.intToByteArray(new String(viruses[i]).hashCode())).getBytes();
            System.out.println(StringUtils.getHexString(removedSection));
            System.out.println(StringUtils.getHexString(viruses[i]));
            logwriter.write(String.format("insert into changes (filepath,loc,dat,vir,hash) values " +
                    "('%s',%d,X'", filepathToChange, locationOfChange).getBytes());
            logwriter.write(removedSectionConvertedToHexString);
            logwriter.write("',X'".getBytes());
            logwriter.write(virusConvertedToHexString);
            logwriter.write("',X'".getBytes());
            logwriter.write(hashConvertedToHexString);
            logwriter.write("');\n".getBytes());

            // Insert virus into file
            File original = new File(filepathToChange);
            original.delete();
            RandomAccessFile fileToInsertIn = new RandomAccessFile(filepathToChange + ".tmp", "rw");
            fileToInsertIn.seek(locationOfChange);
            fileToInsertIn.write(viruses[i]);
            fileToInsertIn.close();

            File a = new File(filepathToChange + ".tmp");
            original = new File(filepathToChange);
            a.renameTo(original);
            a.delete();

            logwriter.close();
        }


    } catch (Exception e)
    {   
        System.err.println(e.toString());
        System.err.println("Error: InsertVirusesIntoCorpus, line 100");
    }
}

有任何想法嗎？

Answer 1

您的代碼讓我有些困惑，為什么要進行如此多的轉換，但是我在這里...

我的直覺告訴我，您要么無意間進行了一些字符集轉換，要么損壞是由於在原始字節，Java字節原語和Java int原語之間移動而引起的。 請記住，Java的byte值范圍在-127到128之間，並且String的.getBytes（）支持字符編碼方案。

具體來說，這對我來說真的很奇怪：

byte[] virusConvertedToHexString = StringUtils.getHexString(viruses[i]).getBytes();

這是正在發生的事情：

1. viruses[i]給您一個byte數組
2. StringUtils.getHexString()采用的是字節數組，並為您提供了一個十六進制表示byte數組作為String （假設：這是什么StringUtils它似乎不從？ [org.apache.commons.lang][1] ）
3. 最后，將String的byte數組存儲到virusConvertedToHexString

第2步是我懷疑會遇到麻煩。

另外，上面的代碼塊不包含生成的代碼：

//From the file that is read from. added ** to emphasize the corrupted byte
insert into viruses (virusSig,virusHash) values (
X'579fdc569b170419e15750f0feb360aa9c58d8**90**eede50def97ee7cb03b9e905',
X'ee002fe5');

這會有所幫助。