具有目標值或鍵的對象的 jq 過濾器不存在

Question

我有 jsonlines 數據，我想找到 1. value is empty object 或 2. key is not exist 。 在下面的示例中，我想知道 .items.spec.resource={} 或 .items.spec.limits|requests which key 不存在的項目的結果。

data='{"items":[{"metadata":{"name":"pod01"},"spec":{"containers":[{"name":"con01_01","resources":{"limits":{"cpu":"100m"},"requests":{"cpu":"100m"}}},{"name":"con01_02","resources":{"limits":{"cpu":"100m"},"requests":{"cpu":"100m"}}}]}},{"metadata":{"name":"pod02"},"spec":{"containers":[{"name":"con02_01","resources":{"limits":{"cpu":"100m"},"requests":{"cpu":"100m"}}},{"name":"con02_02","resources":{"limits":{"cpu":"100m"}}}]}},{"metadata":{"name":"pod03"},"spec":{"containers":[{"name":"con03_01","resources":{"limits":{"cpu":"100m"},"requests":{"cpu":"100m"}}},{"name":"con03_02","resources":{}}]}}]}'

list=$(echo $data | jq '.items[] | select(.spec.containers[].resources.requests == null or  .spec.containers[].resources.limits == null or .spec.containers[].resources == {})')

echo $list 

結果來了

{ 
  "metadata": { "name": "pod02" }, 
  "spec": { 
    "containers": [ 
      { "name": "con02_01", 
        "resources": { 
                       "limits": { "cpu": "100m" }, 
                       "requests": { "cpu": "100m" } 
                     } 
      }, 
      { "name": "con02_02", 
        "resources": { 
                       "limits": { "cpu": "100m" } 
                     } 
      } 
    ] 
  } 
} 
{ 
  "metadata": { "name": "pod03" },
  "spec": {
    "containers": [ 
      { 
        "name": "con03_01", 
        "resources": { 
                       "limits": { "cpu": "100m" }, 
                       "requests": { "cpu": "100m" } 
                     } 
      }, 
      { "name": "con03_02", 
        "resources": {} 
      } 
    ] 
  } 
} 

{ 
  "metadata": { "name": "pod03" }, 
  "spec": { 
    "containers": [ 
      { "name": "con03_01", 
        "resources": { 
                        "limits": { "cpu": "100m" }, 
                        "requests": { "cpu": "100m" } 
                     } 
      }, 
      { "name": "con03_02", 
        "resources": {} 
      } 
    ] 
  } 
} 
  
{ 
  "metadata": { "name": "pod03" }, 
  "spec": { 
    "containers": [ 
      { "name": "con03_01", 
        "resources": { 
                        "limits": { "cpu": "100m" }, 
                        "requests": { "cpu": "100m" } 
                      } 
      }, 
      { "name": "con03_02", 
        "resources": {} 
      } 
    ] 
  } 
}

重復部分沒看懂，估計是條件的原因，上面條件的部分怎么才能得到，我想過濾一下metadata和spec.containers符合條件的部分。

Answer 1

根據您的解釋性評論，您似乎可以使用 jq "$-variables" 實現您想要的：

jq -c '
.items[]
| .metadata.name as $podname
| .spec.containers[] 
| select(.resources.requests == null or 
         .resources.limits == null or 
         .resources == {})
| [$podname, .name]
'

使用您的數據，上面產生的輸出將是：

["pod02","con02_02"]
["pod03","con03_02"]

簡化

第三個條件（.resources == {}）的測試實際上是多余的，所以上面的jq過濾器相當於：

.items[]
| .metadata.name as $podname
| .spec.containers[] 
| select(.resources | (.requests == null or .limits == null ))
| [$podname, .name]

鍵的存在

要檢查鍵是否存在，通常使用has/1是合適的，因為{} | .key {} | .key計算結果為null 。 因此，您可能希望將上面的select()替換為：

select( any(.resources | has("requests", "limits"); not) )