[英]How can I return a PHP array to the javascript function that called it
[英]How can i return an array in php function
我需要函數中的返回數組。 當我使用返回這個數組()時:
function menuOlustur($ana_kategoriler){
global $db;
$alt_kategori_durum = '';
$alt_kategori;
foreach ($ana_kategoriler as $kategori) {
$alt_kategori = $db->rawQuery('select * from s_kategoriler where kategori = ' . $kategori['id'] . ' and durum=1 order by sira asc');
}
return $alt_kategori;
}
我正在使用它返回數組中的另一個索引。
function menuOlustur($ana_kategoriler){
global $db;
$alt_kategori_durum = '';
$alt_kategori;
foreach ($ana_kategoriler as $kategori) {
$alt_kategori[] = $db->rawQuery('select * from s_kategoriler where kategori = ' . $kategori['id'] . ' and durum=1 order by sira asc');
}
return $alt_kategori;
}
我的 $ana_kategoriler 是一個數組,它是一個這樣的調用查詢
$ana_k_cek = $db->rawQuery('select id, kategori, adi_' . $dil . ' as adi,link_' . $dil . ' as link from s_kategoriler where m_id=5 and durum=1 order by sira asc ');
我能做什么?
編輯:固定查詢,不應該是 kategori = 1,2,3,4,而是 kategory IN(1,2,3,4)
我建議將您的代碼更改為:
function menuOlustur($ana_kategoriler){
global $db;
/* first - collect all ids */
$ids = array();
foreach ($ana_kategoriler as $kategori) {
$ids[] = $kategori['id'];
}
/* return empty array if there is no ids, or return result of single query matching all results with given ids */
return count($ids) > 0 ? $db->rawQuery('select * from s_kategoriler where kategori IN( ' . implode(",",$ids) . ') AND durum=1 order by sira asc') : array();
}
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