Oracle SQL 查詢以獲取基於記錄的最小和最小日期

Question

輸入：

date1, id, device1, device2
1jul,  1, enable, disable
2jul, 1, enable , disable
3jul, 1, enable, disable
4jul, 1, unknown, enable
5jul, 1, enable, disable
6jul, 1, enable, disable

如何獲得低於輸出：

id, device1,device2, mindate, maxdate
1, enable, disable, 1jul, 3jul
1, unknown, enable, 4jul, 4jul
1, enable, disable, 5th, 6th

Answer 1

這是一種間隙和島嶼問題。 在這種情況下，行號的差異可能是最簡單的解決方案：

select id, device1, device2, min(date1), max(date1)
from (select t.*,
             row_number() over (partition by id, device1, device2 order by date1) as seqnum_2,
             row_number() over (partition by idorder by date1) as seqnum
      from t
     ) t
group by id, device1, device2, (seqnum - seqnum_2)