從 CTE 中的 select 語句中的 case 中獲取值的 Sql 查詢

Question

我正在嘗試編寫 SQL。 在此，我希望輸出中的列 Bank 和 Y-Bank。 Y-Bank 是根據某些案例陳述計算的，使用 CTE，但我無法將 Y-Plant 作為列返回。

我還創建了一個表，如此處的輸入/輸出所示： https : //dbfiddle.uk/?rdbms=mysql_8.0&fiddle=749e4ca1570880e9c64c4553d18dea1a

下面是代碼：

WITH CTE AS
(
SELECT
"BANK",
(select 
case 
when "TEST"=0 AND "TEST1">0
THEN ( SELECT COUNT("ZONES")FROM mytable I WHERE  I.BANK = O.BANK AND I."ZONES"='Y' )
END AS "Y-BANK"
from(
  
 (SELECT  
         
          CASE WHEN ( (SELECT COUNT("ZONES")FROM mytable I WHERE I.BINDER = O.BINDER AND I."ZONES"='N' ) = 0 ) AND ( (SELECT COUNT("ZONES")FROM mytable I WHERE I.BINDER = O.BINDER AND I."ZONES"='Y' ) > 0 )
    THEN ( SELECT COUNT("ZONES")FROM mytable I WHERE  I."TOTAL LINE"= O."TOTAL LINE"AND I."ZONES"='N' )
  END AS "TEST",
          CASE WHEN ( (SELECT COUNT("ZONES")FROM mytable I WHERE I.BINDER = O.BINDER AND I."ZONES"='' ) = 0 ) AND ( (SELECT COUNT("ZONES")FROM mytable I WHERE I.BINDER = O.BINDER AND I."ZONES"='Y' ) > 0 )
       THEN ( SELECT COUNT("ZONES")FROM mytable I WHERE  I."TOTAL LINE" = O."TOTAL LINE" AND I."ZONES"='Y' )
  END AS "TEST1"
  from mytable )
  )
  )
FROM mytable O
)
 


SELECT *
FROM CTE O

有人可以幫助我解決如何糾正它嗎？

Answer 1

如果我理解正確，您想計算每個銀行的“Y”值的數量。 您可以使用窗口函數：

select t1.*, sum(zones = 'Y') over (partition by Bank1) as y_bank
from t1

這是一個 db<>fiddle。

Answer 2

您可以使用以下查詢

select 
   bank1 as "bank",
   (select count(*)over(partition by Bank1,Zones order by Bank1 desc) as "y_bank" from t1 where Zones = 'Y' and Bank1 = t.Bank1 limit 1) as "y_bank"
from t1 t