使用套接字發送獲取請求的問題 (PYTHON)

Question

我的代碼：

import socket
request = b"GET / HTTP/1.1\nHost: api16-normal-c-useast1a.tiktokv.com\n\n"
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect(("api16-normal-c-useast1a.tiktokv.com/aweme/v1/aweme/favorite/?max_cursor=0&count=0&ac=wifi&aid=1180&user_id=6986127446509143000", 80))
s.send(request)
result = s.recv(10000)
while (len(result) > 0):
    print(result)
    result = s.recv(10000)

我的錯誤：

Traceback (most recent call last):
  File "test.py", line 4, in <module>
    s.connect(("api16-normal-c-useast1a.tiktokv.com/aweme/v1/aweme/favorite/?max_cursor=0&count=0&ac=wifi&aid=1180&user_id=6986127446509143000", 80))
socket.gaierror: [Errno 11001] getaddrinfo failed

任何幫助表示贊賞謝謝！。

Answer 1

connect的參數應該只包含一個域名，並在請求本身中提供請求路徑。 您應該將代碼更改為以下內容：

import socket
request = b"GET /aweme/v1/aweme/favorite/?max_cursor=0&count=0&ac=wifi&aid=1180&user_id=6986127446509143000 HTTP/1.1\nHost: api16-normal-c-useast1a.tiktokv.com\n\n"
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect(("api16-normal-c-useast1a.tiktokv.com", 80))
s.send(request)
result = s.recv(10000)
while (len(result) > 0):
    print(result)
    result = s.recv(10000)