嘗試使用 run_forever 創建一個永遠運行的異步函數

Question

我正在嘗試訪問 websocket 來監聽一些信息，所以我想使用 run_forever 命令繼續監聽直到我停止程序，但是當我收到下面的錯誤時，有人能告訴我我做錯了什么嗎？

代碼：

loop = asyncio.get_event_loop()

async def listen():
    url = "websocket url starting with wss"

    async with websockets.connect(url) as ws:
        msg = await ws.recv()
        print(msg)


loop.run_forever(listen())

然后錯誤說：

RuntimeWarning: coroutine 'listen' was never awaited
  loop.run_forever(listen())
RuntimeWarning: Enable tracemalloc to get the object allocation traceback
Traceback (most recent call last):
  File "C:\Users\...", line 18, in <module>
    loop.run_forever(listen())
TypeError: run_forever() takes 1 positional argument but 2 were given

Answer 1

我嘗試將您的腳本加載到 Python 3.9.6 中，但我看到了您的錯誤。

這是我運行它的方式（您需要輸入正確的 URL）：

import asyncio, websockets

async def listen():
    url = "websocket url starting with wss"
    async with websockets.connect(url) as ws:
        msg = await ws.recv()
        print(msg)

async def main():
    loop = asyncio.get_event_loop()
    loop.run_forever(await listen())

if __name__ == "__main__":
    asyncio.run(main())

我希望它可以幫助您進一步了解您的程序。