遍歷嵌套的字典值並返回基於字典值的有序列表

Question

我有一個名為“transportation_costs”的嵌套字典，其中包含與每個設施-客戶組合相關的運輸成本。 我需要遍歷字典中的每個客戶 (key2) 並生成五個有序列表（每個客戶一個），其中包含根據嵌套字典中的值對給定客戶從最便宜到最昂貴排名的設施。

*** 當我說“最便宜”時，我的意思是它的運輸成本更低。

 transportation_cost=
                     {'Fac-1' : {"Apple":4,"Samsung":5,"Huawei":6,"Nokia":8,"Motorolla":10},
                      'Fac-2' : {"Apple":6,"Samsung":4,"Huawei":3,"Nokia":5,"Motorolla":8},
                      'Fac-3' : {"Apple":9,"Samsung":7,"Huawei":4,"Nokia":3,"Motorolla":4},
                      'Fac-4' : {"Apple":3,"Samsung":4,"Huawei":8,"Nokia":4,"Motorolla":4},
                      'Fac-5' : {"Apple":4,"Samsung":7,"Huawei":5,"Nokia":3,"Motorolla":2}}

我需要最終的輸出是這樣的：

         "Apple" = ['FAC-4', 'FAC-5', 'FAC-3', 'FAC-2','FAC-1']
         "Samsung" = ['FAC-2', 'FAC-4', 'FAC-3', 'FAC-5','Fac-1']
         "Huawei"=  ['FAC-3', 'FAC-5', 'FAC-1', 'FAC-4','FAC-2']
         "Nokia" = ['FAC-5', 'FAC-3', 'FAC-2', 'FAC-4','FAC-1']
         "Motorolla" = ['FAC-5', 'FAC-1', 'FAC-3', 'FAC-2', 'FAC-4']

Answer 1

嘗試：

all_keys = set(k for v in transportation_cost.values() for k in v.keys())
out = {
    k: [
        *sorted(
            transportation_cost.keys(), key=lambda x: transportation_cost[x][k]
        )
    ]
    for k in all_keys
}
print(out)

印刷：

{
    "Huawei": ["Fac-2", "Fac-3", "Fac-5", "Fac-1", "Fac-4"],
    "Motorolla": ["Fac-5", "Fac-3", "Fac-4", "Fac-2", "Fac-1"],
    "Apple": ["Fac-4", "Fac-1", "Fac-5", "Fac-2", "Fac-3"],
    "Nokia": ["Fac-3", "Fac-5", "Fac-4", "Fac-2", "Fac-1"],
    "Samsung": ["Fac-2", "Fac-4", "Fac-1", "Fac-3", "Fac-5"],
}