[英]How can I get children attribute + parent element
我想編寫一個 SQL 服務器存儲過程來解析 XML 數據以檢索值:
DECLARE @Champs TABLE
(
NU_LINE VARCHAR(4),
"KEY" VARCHAR(200),
LABEL VARCHAR(200),
API_NAME VARCHAR(200),
API_FIELD VARCHAR(200),
"VALUE" VARCHAR(MAX)
);
DECLARE @docHandle int;
DECLARE @xmlDocument nvarchar(max); -- or xml type
SET @xmlDocument = N'<STRUCTURE>
<GRILLE>
<ROWS>
<ROW>
<NU_LINE>1</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="AAA" API_NAME="AAA" API_FIELD="BBB" VALUE="ABC123" />
<CHAMP KEY="RES" LABEL="AAA" API_NAME="AAA" API_FIELD="BBB" VALUE="JAMES" />
<CHAMP KEY="DATE_BEGIN" API_NAME="CCC" API_FIELD="BBB" VALUE="14/08/2021" />
<CHAMP KEY="DATE_END" API_NAME="CCC" API_FIELD="BBB" VALUE="28/08/2021" />
</CHAMPS>
</ROW>
<ROW>
<NU_LINE>2</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="ABC" API_NAME="DDD" API_FIELD="EEE" VALUE="CDE345" />
<CHAMP KEY="DATE_RES" LABEL="CDE" API_NAME="DDD" API_FIELD="EEE" VALUE="06/05/2021" />
<CHAMP KEY="RES" LABEL="DEF" API_NAME="DDD" API_FIELD="EEE" VALUE="JOHN" />
<CHAMP KEY="DATE_BEGIN" API_NAME="DDD" API_FIELD="EEE" VALUE="07/08/2021" />
<CHAMP KEY="DATE_END" API_NAME="DDD" API_FIELD="EEE" VALUE="14/08/2021" />
</CHAMPS>
</ROW>
<ROW>
<NU_LINE>3</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="EFG567" />
<CHAMP KEY="DATE_RES" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="10/05/2021" />
<CHAMP KEY="RES" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="JIM" />
<CHAMP KEY="DATE_BEGIN" API_NAME="FFF" API_FIELD="GGG" VALUE="24/07/2021" />
<CHAMP KEY="DATE_END" API_NAME="FFF" API_FIELD="GGG" VALUE="31/07/2021" />
</CHAMPS>
</ROW>
</ROWS>
</GRILLE>
</STRUCTURE>'
EXEC sp_xml_preparedocument @docHandle OUTPUT, @xmlDocument;
-- Use OPENXML to provide rowset consisting of customer data.
INSERT @Champs
SELECT *
FROM OPENXML(@docHandle, N'/STRUCTURE/GRILLE/ROWS/ROW/CHAMPS/CHAMP')
WITH (NU_LINE VARCHAR(4), "KEY" VARCHAR(200), LABEL VARCHAR(200), API_NAME VARCHAR(200), API_FIELD VARCHAR(200), "VALUE" VARCHAR(MAX))
SELECT * FROM @Champs
但在我的結果中, NU_LIGNE
始終是 null。
我該怎么做才能分別為每一行獲取 NU_LINE 1、2 或 3?
非常感謝。
正如我在評論中提到的,不要使用那些舊程序; 它們的存在是為了與 SQL Server 2000兼容。 SQL 服務器自 2005 年以來一直支持 XQUERY,因此您沒有理由不在 16 年后使用它。 如果你這樣做,這就簡單多了:
DECLARE @xmlDocument xml;
SET @xmlDocument = N'<STRUCTURE>
<GRILLE>
<ROWS>
<ROW>
<NU_LINE>1</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="AAA" API_NAME="AAA" API_FIELD="BBB" VALUE="ABC123" />
<CHAMP KEY="RES" LABEL="AAA" API_NAME="AAA" API_FIELD="BBB" VALUE="JAMES" />
<CHAMP KEY="DATE_BEGIN" API_NAME="CCC" API_FIELD="BBB" VALUE="14/08/2021" />
<CHAMP KEY="DATE_END" API_NAME="CCC" API_FIELD="BBB" VALUE="28/08/2021" />
</CHAMPS>
</ROW>
<ROW>
<NU_LINE>2</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="ABC" API_NAME="DDD" API_FIELD="EEE" VALUE="CDE345" />
<CHAMP KEY="DATE_RES" LABEL="CDE" API_NAME="DDD" API_FIELD="EEE" VALUE="06/05/2021" />
<CHAMP KEY="RES" LABEL="DEF" API_NAME="DDD" API_FIELD="EEE" VALUE="JOHN" />
<CHAMP KEY="DATE_BEGIN" API_NAME="DDD" API_FIELD="EEE" VALUE="07/08/2021" />
<CHAMP KEY="DATE_END" API_NAME="DDD" API_FIELD="EEE" VALUE="14/08/2021" />
</CHAMPS>
</ROW>
<ROW>
<NU_LINE>3</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="EFG567" />
<CHAMP KEY="DATE_RES" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="10/05/2021" />
<CHAMP KEY="RES" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="JIM" />
<CHAMP KEY="DATE_BEGIN" API_NAME="FFF" API_FIELD="GGG" VALUE="24/07/2021" />
<CHAMP KEY="DATE_END" API_NAME="FFF" API_FIELD="GGG" VALUE="31/07/2021" />
</CHAMPS>
</ROW>
</ROWS>
</GRILLE>
</STRUCTURE>';
SELECT R.R.value('(NU_LINE/text())[1]','int') AS NU_LINE,
C.C.value('@KEY','varchar(200)') AS [KEY],
C.C.value('@LABEL','varchar(200)') AS [LABEL],
C.C.value('@API_NAME','varchar(200)') AS [API_NAME],
C.C.value('@API_FIELD','varchar(200)') AS [API_FIELD],
C.C.value('@VALUE','varchar(MAX)') AS [VALUE]
FROM @xmlDocument.nodes('/STRUCTURE/GRILLE/ROWS/ROW')R(R)
CROSS APPLY R.R.nodes('CHAMPS/CHAMP')C(C);
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