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[英]How to run a C program and get output of the program using Twisted Python
[英]How to exit the program after max 3 attempts using Python, for exception program , if you dont get the desired output?
對於異常程序,如果您沒有獲得所需的輸出,如何在使用 Python 最多 3 次嘗試后退出程序?
while True:
try:
x = int(input("Please enter a number: "))
break
#except Exception as e:
# print (e)
except ValueError:
print ("You have entered the non-numeric value. Enter the numerical value.")
except KeyboardInterrupt:
print ("\nYou have press Ctr+C.")
exit (1)
nothing = 0
while nothing < 3:
nothing += 1
try:
x = int(input("Please enter a number: "))
break
#except Exception as e:
# print (e)
except ValueError:
print ("You have entered the non-numeric value. Enter the numerical value.")
except KeyboardInterrupt:
print ("\nYou have press Ctr+C.")
break
嘗試:
c = 0
while c < 3:
c += 1
try:
x = int(input("Please enter a number: "))
break
except ValueError:
print ("You have entered the non-numeric value. Enter the numerical value.")
except KeyboardInterrupt:
print ("\nYou have press Ctr+C.")
break
您想在 3 次嘗試后退出。 試試這個並計算輸入是錯誤的:
num_err = 0
while num_err < 3:
try:
x = int(input("Please enter a number: "))
except ValueError:
print ("You have entered the non-numeric value. Enter the numerical value.")
num_err += 1
except KeyboardInterrupt:
print ("\nYou have press Ctr+C.")
break
使用sys.exit()
停止整個腳本
import sys
while True:
try:
x = int(input("Please enter a number: "))
#except Exception as e:
# print (e)
except ValueError:
print ("You have entered the non-numeric value. Enter the numerical value.")
except KeyboardInterrupt:
print ("\nYou have press Ctr+C.")
sys.exit()
我閱讀了上面提交的所有代碼,但缺少一件事,如果用戶enter
兩個錯誤的值,然后enter
一個正確的值,他只有一次機會。 也就是說,如果用戶在輸入兩個正確的input
后enter
任何錯誤的input
,則循環將中斷。
所以我試圖解決這個問題。 看我的代碼...
count = 0
while True:
try:
x = int(input("Please enter a number: "))
count = 0
break
except ValueError:
count += 1
print("You have entered the non-numeric value.Only three invalid inputs are allowed. Enter the numerical value.")
except KeyboardInterrupt:
print("\nYou have press Ctr+C.")
exit(1)
if count == 3:
break
我試圖解釋我在這段code
中寫的內容。 正如您所提到的,用戶只能enter
三個invalid
input
,因此每次user
enter
invalid
input
時,我都會增加variable
count
。 但如果user
enter
有效input
,則count
將為0
。 這意味着user
最多可以enter
三個invalid
input
。 連續entering
三個invalid
input
后count
為3
, loop
break
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