將鍵數組和值數組合並到 JavaScript 中的對象中

Question

我有：

var keys = [ "height", "width" ];
var values = [ "12px", "24px" ];

我想把它轉換成這個對象：

{ height: "12px", width: "24px" }

在 Python 中，有簡單的習語dict(zip(keys,values)) 。 在 jQuery 或純 JavaScript 中是否有類似的東西，或者我必須做很長的路嗎？

Answer 1

使用 Array reduce的最簡單的 ES6 單行解決方案：

const keys = ['height', 'width'];
const values = ['12px', '24px'];
const merged = keys.reduce((obj, key, index) => ({ ...obj, [key]: values[index] }), {});

Answer 2

簡單的 JS 函數是：

function toObject(names, values) {
    var result = {};
    for (var i = 0; i < names.length; i++)
         result[names[i]] = values[i];
    return result;
}

當然你也可以實際實現像 zip 等函數，因為 JS 支持高階類型，這使得這些函數式語言主義變得容易：D

Answer 3

使用 lodash。

_.zip對象

例子

_.zipObject(['a', 'b'], [1, 2]);
// ➜ { 'a': 1, 'b': 2 }

Answer 4

作為替代解決方案，我認為尚未提及：

  var result = {};
  keys.forEach((key, idx) => result[key] = values[idx]);

Answer 5

您可以使用map方法組合兩個數組，然后使用Object.fromEntries將其轉換。

 var keys = ["height", "width"]; var values = ["12px", "24px"]; var array = keys.map((el, i) => { return [keys[i], values[i]]; }); // → [["height", "12px"], ["width", "24px"]] var output = Object.fromEntries(array); // → {height: "12px", width: "24px"} console.log(output);

Answer 6

考慮到不變性的功能方法：

 const zipObj = xs => ys => xs.reduce( (obj, x, i) => ({...obj, [x]: ys[i] }), {}) const arr1 = ['a', 'b', 'c', 'd'] const arr2 = ['e', 'f', 'g', 'h'] const obj = zipObj (arr1) (arr2) console.log (obj)

Answer 7

您可以使用reduce()函數將鍵值對映射到一個對象。

 /** * Apply to an existing or new object, parallel arrays of key-value pairs. * * @param {string[]} keys - List of keys corresponding to their accociated values. * @param {object[]} vals - List of values corresponding to their accociated keys. * @param {object} [ref={}] - Optional reference to an existing object to apply to. * * @returns {object} - The modified or new object with the new key-value pairs applied. */ function toObject(keys, vals, ref) { return keys.length === vals.length? keys.reduce(function(obj, key, index) { obj[key] = vals[index]; return obj; }, ref || {}): null; } var keys = [ "height", "width" ]; var values = [ "12px", "24px" ]; document.body.innerHTML = '<pre>' + JSON.stringify(toObject(keys, values), null, 2) + '</pre>';

Answer 8

現在我們有了Object.fromEntries我們可以做類似的事情：

 const keys = [ "height", "width" ]; const values = [ "12px", "24px" ]; const myObject = Object.fromEntries( values.map((value, index) => [keys[index], value]) ); console.log(myObject);

Answer 9

您可以轉置數組並獲取包含條目的對象。

 const transpose = (r, a) => a.map((v, i) => [...(r[i] || []), v]), keys = [ "height", "width" ], values = [ "12px", "24px" ], result = Object.fromEntries([keys, values].reduce(transpose, [])); console.log(result);

Answer 10

這是一個包含所有常量（非修改）且沒有庫的示例。

 const keys = ["Adam", "Betty", "Charles"]; const values = [50, 1, 90]; const obj = keys.reduce((acc, key, i) => { acc[key] = values[i]; return acc; }, {}); console.log(obj);

或者，如果您考慮使用庫，則可以使用lodash zipobject來完成您的要求。

Answer 11

function combineObject( keys, values)
{
    var obj = {};
    if ( keys.length != values.length)
       return null;
    for (var index in keys)
        obj[keys[index]] = values[index];
     return obj;
};


var your_obj = combine( your_keys, your_values);

Answer 12

這是一個將嵌套數組轉換為多個鍵值對象數組的方法。

 var keys = [ ['#000000', '#FFFFFF'], ['#FFFF00', '#00FF00', '#00FFFF', '#0000FF'], ]; var values = [ ['Black', 'White'], ['Yellow', 'Green', 'Cyan', 'Blue'], ]; const zipObj = xs => ys => xs.reduce( (obj, x, i) => ({...obj, [x]: ys[i] }), {}) var array = keys.map((el, i) => zipObj (keys[i]) (values[i])); console.log(array);

輸出是

[
  {
    "#000000": "Black",
    "#FFFFFF": "White"
  },
  {
    "#FFFF00": "Yellow",
    "#00FF00": "Green",
    "#00FFFF": "Cyan",
    "#0000FF": "Blue"
  }
]

Answer 13

提供帶有for...of循環的解決方案。

 var keys = ["height", "width"]; var values = ["12px", "24px"]; const result = {}; for (let [index, key] of keys.entries()) result[key] = values[index]; console.log(result);

您還可以使用像ramda這樣具有zipObj功能的庫。 例子：

 const keys = ["height", "width"]; const values = ["12px", "24px"]; const result = R.zipObj(keys, values); console.log(result);

Answer 14

在jQuery-Utils項目中， ArrayUtils模塊實現了zip功能。

//...
zip: function(object, object2, iterator) {
    var output = [];
    var iterator = iterator || dummy;
        $.each(object, function(idx, i){
        if (object2[idx]) { output.push([i, object2[idx]]); }
    });
    return output;
}
//...