[英]take all lines between two pattern by Regex
我用了
(?<=<li>)..(?=</li>)像這樣只有一行:
pattern1 Everything pattern2
<pre> pattern1 line1 line2 line3 line4 line5 pattern2 </pre>
對於許多行,您可能需要選項re.DOTALL
和/或re.MULTILINE
text = '''<pre>
pattern1
line1
line2
line3
line4
line5
pattern2
</pre>'''
import re
result = re.findall('pattern1(.*)pattern2', text, re.DOTALL)
print('len:', len(result))
print(result[0].strip())
結果:
len: 1
line1
line2
line3
line4
line5
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.